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den301095 [7]
3 years ago
13

Step by step explanation need it

Mathematics
1 answer:
nasty-shy [4]3 years ago
4 0

Answer:

8/17

Step-by-step explanation:

The sine of an angle is defined as the opposite side to the reference angle divided by the hypotenuse.

The side opposite the angle is always the side not connected to the reference angle. In this case the opposite side = ZY

The hypotenuse = XZ

Sin(X) = ZY/XZ

Sin(X) = 1634 = 8 / 17

You might be interested in
You have 36
lara31 [8.8K]

Answer:

36 times 2 is 72

Step-by-step explanation:

That is what you're asking right? I'm just going by the last one.

6 0
3 years ago
Read 2 more answers
consider the function and then use calculus to answer the questions that follow 1 1/x 5/x^2 1/x^3 (a) Find the interval(s) where
boyakko [2]

Answer:

a)X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

b)Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

Step-by-step explanation:

From the question we are told that

The Function

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

Generally the differentiation of function f(x) is mathematically solved as

f(x)=1+\frac{1}{x}  +\frac{5}{x^2} +\frac{1}{x^3}

f(x)=\frac{x^3+x^2+5x+1}{x^2}

Therefore

f'(x)=\frac{x^2+10x+3}{x^4}

Generally critical point is given as

f'(x)=0

\frac{x^2+10x+3}{x^4}=0

x=-5 \pm\sqrt{22}

Generally the maximum and minimum x value for critical point is mathematically solved as

f'(-5 \pm\sqrt{22})

Where

Maximum value of x

f'(-5 +\sqrt{22})

Minimum value of x

f'(-5 +\sqrt{22})

Therefore interval of increase is mathematically given by

f'(-5 -\sqrt{22}),f'(-5 +\sqrt{22})

f(x)

Therefore interval of decrease is mathematically given by

(-\infty,-5 -\sqrt{22}),f'(-5 +\sqrt{22},0),(0,\infty)

Generally the second differentiation of function f(x) is mathematically solved as

f''(x)=\frac{2(x^2+15x+6)}{x^5}

Generally the point of inflection is mathematically solved as

f''(x)=0

x^2+15x+6=0

Therefore inflection points is given as

x=\frac{1}{2} (-15 \pm \sqrt{201}

f''(x)>0,\frac{1}{2}(-15-\sqrt{201})

a)Generally the concave upward interval X is mathematically given as

X=((-15-\sqrt{201},(-15+\sqrt{201}),(0,\infty)

f''(x)

b)Generally the concave downward interval Y is mathematically given as

Y=(\infty,\frac{1}{2}(-15-\sqrt{201} ) ),(\frac{1}{2}()-15+\sqrt{201)},0  )

5 0
2 years ago
9 + 4 to the third power x (20-8) / 2 + 6
harkovskaia [24]

1110.5 is the answer and your welcome

5 0
2 years ago
Can somebody help me with this
EastWind [94]

Answer:

D = -1, -1, 2, 5

R = 0, 2, 3, 7

✅It is NOT A FUNCTION

Step-by-step explanation:

D (Domain) = input values (x-values)

D = -1, -1, 2, 5

R (Range) = output values

R = 0, 2, 3, 7

✅It is not a function because an x-value, -1, has two different y-values, 7 and 2, assigned to it.

7 0
2 years ago
Simplify 5x + 2(x - 3) = -2(x - 1)
Kruka [31]

Answer:

x=8/9

Step-by-step explanation:

5x+2(x-3)=-2(x-1)

1) Distribute 2 to x and -3:

5x+2x-6=-2(x-1)

2) Distribute -2 to x and -1:

5x+2x-6=-2x+2

3) Combine alike terms:

7x-6=-2x+2

4) Add 2x to both sides:

9x-6=2

5) Add 6 to both sides:

9x=8

6) Divide both sides by 9:

x=8/9

8 0
3 years ago
Read 2 more answers
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