1.) 1+10a-5a
Subtract 5a from 10a
Final Answer: 1+5a
3.) x-9-3x
Subtract 3x from x
Final Answer: -9-2x
5.) 1-4n+2n-1
Subtract 1 from 1
-4n+2n
Add
Final Answer: -2n
7.) 10k-3k
Subtract
Final Answer: 7k
9.) 5r+4-4
Subtract
Final Answer: 5r
Answer: In the resulting equation: " a² - 12a + 32 = 0 " ;
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The "coefficient" of the "a" term is: " - 12" .
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The "constant" is: " 32 " .
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Explanation:
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Let: "a = x² + 4 " .
Given: (x² + 4)² + 32 = 12x² + 48 ;
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Factor: "12x² + 48" into " (x² + 4) " ;
"12x² + 48" = 12 (x² + 4) " ;
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Given: (x² + 4)² + 32 = 12x² + 48 ;
rewrite as; "a² + 32 = 12a " ;
Subtract "12a" from each side of the equation;
"a² + 32 - 12a = 12a - 12a ;
to get:
" a² - 12a + 32 = 0 " .
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The coefficient of the "a" term; that is:
The "coefficient" of " -12a" ; is: "- 12" .
The constant is: "32<span>" .
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Answer:
see below
Step-by-step explanation:
DB = 9 units (by counting)
BA = 12 units (by counting)
DA can be found by using the pythagorean theorem
a^2 +b^2 = c^2
BD^2 + BA^2 = DA ^2
9^2 +12^2 = DA^2
81 +144 = DA^2
225 = DA ^2
Take the square root of each side
sqrt(225) = sqrt(DA^2)
15 = DA
LJ = 3 units (by counting)
JK = 4 units (by counting)
LK can be found by using the pythagorean theorem
a^2 +b^2 = c^2
LJ^2 + JK^2 = LK ^2
3^2 +4^2 = LK^2
9 +116 = LK^2
25 = LK ^2
Take the square root of each side
sqrt(25) = sqrt(LK^2)
5 = LK
Scale factor from BAD to JKL
15 to 5
Divide each side by 5
3 to 1
We multiply by 1/3 to go from the big to small
Factor out the greatest common factor from each group.
Group the first two terms and the last two terms.
(
−4x)+2xy−8y
Factor out the greatest common factor (GCF) from each group.
x(x−4)+2y(x−4)
Factor the polynomial by factoring out the greatest common factor, x−4.
(x−4)(x+2y)
I believe this is correct. Good luck.
Answer:
C
Step-by-step explanation: