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Alina [70]
3 years ago
8

14(x+y)+y-15+3y simplified

Mathematics
2 answers:
eduard3 years ago
8 0

Answer:

answer my question when done thanks``

Step-by-step explanation:

ty

nordsb [41]3 years ago
7 0

Answer:

14x+18y-15

Step-by-step explanation:

Distribute first:

14x plus 14y plus y-15 plus 3y.

Combine Like terms(Anything with the same variable):

14x plus 15y-15 plus 3y.

14x plus 18y-15.

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What is the product?<br><br> (y3+3y+7) x (8y2+y+1)
Nataly [62]

Answer:

I believe that this is what you mean. (y^3+3y+7)*(8y^2+y+1)

Step-by-step explanation:

So your answer would be: 8y^5+y^4+25y^3+59y^2+10y+7

Have a nice day!

I really hope this helps!

5 0
2 years ago
A fifteen-passenger van is rented for a family vacation. The van rental is $60 per day,
bazaltina [42]

Answer:

3d

Step-by-step explanation:

$60 + $145 = $205

$205 x 3 = $615

7 0
2 years ago
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The weight of the larger of two boxes is 2 lbs less than 5 times the weight of the smaller box. Their sum is
olganol [36]

Answer:

It's 74 Because 2 times 5 is 10plus 64 equals 74

5 0
3 years ago
A cylinder and a cone have the same volume. the cylinder has a radius of 2 inches and a height of 3 inches. the cone has a radiu
Sati [7]

Answer:h = y^2 / 27

Step-by-step explanation:

Volume of a cylinder = pi*(xx)^2*yy

= x^4*pi*yy

Volume of a cone = 1/3*pi*(9x^2)^2*h

= 27pi*x^4*h

x^4*pi*y^2 = 27pi*x^4*h

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4 0
3 years ago
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labwork [276]

Given that Noemi makes a bracelet that averages $0.60 per bead, we need to write an equation that models this average bead cost. This can be found by taking the total cost of the beads and dividing it by the number of beads used.

1. The total cost of the beads may be found by multiplying the price of each type of bead by the number used, and then adding these values together. Thus:

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= 0.75x + 0.9

2. Total number of beads = x + 3

3. Thus, the average cost is:

(0.75x + 0.9)/(x + 3)

4. Using the value of the average cost per bead given to us ($0.60), we can now write up the full equation:

0.6 = (0.75x + 0.9)/(x + 3)

6 0
3 years ago
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