For the first one:
m is the slope, or how much the line goes up compared to goes right. In this case, the line goes up 40 every time it goes right 10. We write this as a fraction so 40/10, which simplifies to 4. Therefore the equation would be y = 4x.
For a smoothing constant of 0.2
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 55.6 55.48 52.18 50.15 52.72 52.97 53.38 54.90
Forecast error - -12 -.6 -16.48 – 10.12 12.85 1.28 2.03 7.62 -2.9
The mean square error is 84.12
The mean forecast for period 11 is 54.38
For a smoothing constant of 0.8
Time period – 1 2 3 4 5 6 7 8 9 10
Actual value – 46 55 39 42 63 54 55 61 52
Forecast – 58 48.40 53.68 41.94 41.99 58.80 54.96 54.99 59.80
Forecast error - -12 6.60 -14.68 0.06 21.01 -4.80 0.04 6.01 -7.80The mean square error is 107.17
The mean forecast for period 11 is 53.56
Based on the MSE, smoothing constant of .2 offers a better model since the mean forecast is much better compared to the 53.56 of the smoothing constant of 0.8.
Answer:
The answer is B ( X>6 )
Step-by-step explanation:
2x+4= 16
2x = 16 - 4
2x = 12
x = 12/2
x= 6
x>6
Answer:
The length of the shadow is 48.28 feet.
Step-by-step explanation:
The flagpole at its shadow form a 46, 44, 90 triangle.
Let AB be the flagpole. AC is the shadow.
Let's use the sine law to calculate AC.
Answer:
TSA = 175.84 ft²
Step-by-step explanation:
We are given;
Lateral surface area; A_L = 75.36 ft²
Area of base; A_b = 50.24 ft²
Height of cylinder; h = 3ft
Formula for total surface area of Cylinder is;
TSA = 2πr² + 2πrh
Now, lateral surface area is given by the formula; A_L = 2πrh
Area of base is given by the formula;
A_b = πr²
Thus, let's apply these 2 formulas to the formula for total surface area;
TSA = 2(Area of base) + Lateral surface area
TSA = (2 * 50.24) + 75.36
TSA = 175.84 ft²
