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8090 [49]
3 years ago
8

Minneapolis has a population of 382,578, oakland has a population of 390,724 and wichita has a population of 382,368. Which plac

e could you round to so that the rounded populations of all three cities are different?
Mathematics
2 answers:
OLga [1]3 years ago
8 0
Round to the hundreds place, so the populations are
M=382,500
O=390,700
W=382,300
marin [14]3 years ago
5 0

Answer:

  • Minneapolis has a population of 383,000
  • Oakland has a population of 391,000
  • Wichita has a population of 382,000

Step-by-step explanation:

Minneapolis has a population of 382,578

Oakland has a population of 390,724

Wichita has a population of 382,368

All three cities have 6 places of population.

Round off: If round off digit is more than or equal to 5 then it increases previous digit by 1 .

If round off digit is less than 5 then doesn't change in previous digit.

Round off all population to thousands.

First Round off the number 382,578 to thousands place

382,578 ⇒ hundreds digit is 5. So, thousands place digit will increase by 1

382,578 ⇒ 383,000

390,724 ⇒ hundreds digit is 7. So, thousands place digit will increase by 1

390,724 ⇒ 391,000

382,368 ⇒ hundreds digit is 3. So, thousands place digit will not change.

382,368 ⇒ 382,000

<u>After round off the population:-</u>

  • Minneapolis has a population of 383,000
  • Oakland has a population of 391,000
  • Wichita has a population of 382,000

All three cities are different population.

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A person places $686 in an investment account earning an annual rate of 3.8%, compounded continuously. Using the formula V = Pe^
kykrilka [37]

Answer:

V = $1213.03

Step-by-step explanation:

We can determine the amount of money after 15 years with the given formula:

V = Pe^{rt}   (1)

Where:

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6 0
3 years ago
The equation C = 20n + 35 represents the relationship between the cost of school volleyball uniforms, C, in dollars, and the num
Margaret [11]

The equation represent a linear relation with the y-intercept

representing the amount of initial fee.

Correct response:

1. 28 volleyball uniforms

2. Price per uniform

3. Initial flat order fee

4. 10 fewer volleyball uniform

<h3>Methods used for finding the above values</h3>

The given equation that represents the relationship between the cost of school volleyball uniform is; C = 20·n + 35

Where;

C = The uniform costs

n = The number of volleyball uniform ordered

The maximum amount the school has to spend = $600

1. The number of uniforms the school can buy is given by setting C = 600 as follows;

  • C = 20·n + 35

Therefore;

600 = 20·n + 35

20·n = 600 - 35 = 565

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Rounding down to the nearest whole number, we have;

  • The number of uniforms the school can buy, n = <u>28 volleyball uniforms</u>.

2. The number 20 represent the additional cost for each extra uniform, which is the unit cost therefore;

  • 20 represents a <u>$20 price per uniform</u>.

3. The 35 in the equation represents an initial <u>flat fee</u>, such as an

ordering or initial fee, which is fixed.

Therefore;

  • The number 35 represent the <u>fixed cost </u>for producing the uniforms

4. The price per uniform of $30 changes the coefficient of <em>n</em> from 20 to 30 as follows;

C = 30·n + 35

The number of uniforms the school can by with $600 is therefore;

n = \dfrac{600 - 35}{30} = \mathbf{18.8 \overline 3}

Which gives;

The number of uniforms the school can purchase at $30 per uniform is n = 18 volleyball uniforms

The difference in the number of uniforms purchased = 28 - 18 = 10

Therefore;

  • The school can purchase <u>10 fewer uniforms</u> at $30 per uniform

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