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8090 [49]
3 years ago
8

Minneapolis has a population of 382,578, oakland has a population of 390,724 and wichita has a population of 382,368. Which plac

e could you round to so that the rounded populations of all three cities are different?
Mathematics
2 answers:
OLga [1]3 years ago
8 0
Round to the hundreds place, so the populations are
M=382,500
O=390,700
W=382,300
marin [14]3 years ago
5 0

Answer:

  • Minneapolis has a population of 383,000
  • Oakland has a population of 391,000
  • Wichita has a population of 382,000

Step-by-step explanation:

Minneapolis has a population of 382,578

Oakland has a population of 390,724

Wichita has a population of 382,368

All three cities have 6 places of population.

Round off: If round off digit is more than or equal to 5 then it increases previous digit by 1 .

If round off digit is less than 5 then doesn't change in previous digit.

Round off all population to thousands.

First Round off the number 382,578 to thousands place

382,578 ⇒ hundreds digit is 5. So, thousands place digit will increase by 1

382,578 ⇒ 383,000

390,724 ⇒ hundreds digit is 7. So, thousands place digit will increase by 1

390,724 ⇒ 391,000

382,368 ⇒ hundreds digit is 3. So, thousands place digit will not change.

382,368 ⇒ 382,000

<u>After round off the population:-</u>

  • Minneapolis has a population of 383,000
  • Oakland has a population of 391,000
  • Wichita has a population of 382,000

All three cities are different population.

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Step-by-step explanation:

6 0
2 years ago
Read 2 more answers
Give a geometric description of the following system of equations.a. 2x−4y=12 −3x+6y=−15.b. 2x−4y=12 −5x+3y=10.a. 2x−4y=12 −3x+6
Reptile [31]

Answer:

a. No solution, parallel lines.

b. One solution.

Step-by-step explanation:

Given the system of equations:

a. 2x-4y=12

-3x+6y=-15

b. 2x-4y=12

-5x+3y=10

To give a geometric description of the given system of equations.

The geometric description of a system of equations in 2 variables mean the system of equations will represent the number of lines equal to the number of equations in the system given.

i.e.

Number of planes = Number of variables

Number of lines = Number of equations in the system.

Here, we are given 2 variables and 2 equation in each system.

So, they can be represented in the xy-coordinates plane.

And the number of solutions to the system depends on the following condition.

Let the system of equations be:

A_1x+B_1y+C_1=0\\A_2x+B_2y+C_2=0

1. One solution:

There will be one solution to the system of equations,  If we have:

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

2. Infinitely Many Solutions: (Identical lines in the system)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}= \dfrac{C_1}{C_2}

3. No Solution:(Parallel lines)

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Now, let us discuss the system of equations one by one:

a. 2x-4y=12 OR 2x-4y-12=0

-3x+6y=-15 OR -3x+6y+15=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -3, B_2 = 6, C_2= 15

Here, the ratio:

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2} = -\dfrac{2}{3}\\\dfrac{C_1}{C_2} = -\dfrac{4}{5}

\dfrac{A_1}{A_2}=\dfrac{B_1}{B_2}\neq\dfrac{C_1}{C_2}

Therefore, no solution i.e. parallel lines.

b. 2x-4y=12 OR 2x-4y-12=0

-5x+3y=10 OR -5x+3y-10=0

A_1 = 2, B_1 = -4, C_1 = -12\\A_2 = -5, B_2 = 3, C_2 = -10

\dfrac{A_1}{A_2}= -\dfrac{2}{5}\\\dfrac{B_1}{B_2} = -\dfrac{4}{3}\\\dfrac{C_1}{C_2} = -\dfrac{6}{5}

\dfrac{A_1}{A_2}\neq\dfrac{B_1}{B_2}

So, one solution.

Kindly refer to the images attached for the graphical representation of the given system of equations.

6 0
2 years ago
Alguien ayúdeme
VikaD [51]
Hola Senor/Senorita!
6 0
2 years ago
What is the value of k that makes each equation true. For example, 5(ky-6)=15y-30
motikmotik

Answer:

k = 3

Step-by-step explanation:

5(ky-6)=15y-30

Factor out a 5 from the right side

5(ky-6)=5(3y-6)

Divide each side by 5

ky -6 = 3y -6

Add 6 to each side

ky = 3y

divide by y

k = 3

4 0
2 years ago
How do you do this? I am really confused
german

Answer:

Step-by-step explanation:

ok, so this is an infinitly repeating function, so you can write it as:

sqrt(12-x)

Although, x is also equal to sqrt(12-x), so

x = sqrt(12-x), and

x^2 = 12-x

x^2-12+x = 0

now just apply the quadratic formula and you're good

hope i helped :D

8 0
2 years ago
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