Answer:
Can you give me the choices for each of these, I'm not sure how they might phrase it.
280*3= 840
3 journals is about 840 grams
Answer: (20.86, 22.52)
Step-by-step explanation:
Formula to find the confidence interval for population mean :-
![\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%5Cpm%20z%5E%2A%5Cdfrac%7B%5Csigma%7D%7B%5Csqrt%7Bn%7D%7D)
, where
= sample mean.
z*= critical z-value
n= sample size.
= Population standard deviation.
By considering the given question , we have
![\overline{x}= 21.69](https://tex.z-dn.net/?f=%5Coverline%7Bx%7D%3D%2021.69)
![\sigma=3.23](https://tex.z-dn.net/?f=%5Csigma%3D3.23)
n= 58
Using z-table, the critical z-value for 95% confidence = z* = 1.96
Then, 95% confidence interval for the amount of time spent on administrative issues will be :
![21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}](https://tex.z-dn.net/?f=21.69%5Cpm%20%281.96%29%5Cdfrac%7B3.23%7D%7B%5Csqrt%7B58%7D%7D)
![=21.69\pm (1.96)\dfrac{1.7}{7.61577}](https://tex.z-dn.net/?f=%3D21.69%5Cpm%20%281.96%29%5Cdfrac%7B1.7%7D%7B7.61577%7D)
![=21.69\pm (1.96)(0.223221)](https://tex.z-dn.net/?f=%3D21.69%5Cpm%20%281.96%29%280.223221%29)
![\approx21.69\pm0.83](https://tex.z-dn.net/?f=%5Capprox21.69%5Cpm0.83)
![=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)](https://tex.z-dn.net/?f=%3D%2821.69-0.83%2C%5C%2021.69%2B0.83%29%3D%2820.86%2C%5C%2022.52%29)
Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)
Answer:
No mabey c
Step-by-step explanation:
Answer:
3
Step-by-step explanation: