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3 years ago

14

This line has a Y-intercept of A. 0B. 1C.2D.3

2 answers:

anzhelika [568]3 years ago

7 0

Answer:

D

Step-by-step explanation:

insens350 [35]3 years ago

4 0

Answer:

The y-intercept is 3 aka. (0,3)

Step-by-step explanation:

The slope is 1 (since (6-4)/(3-1)=2/2=1)

y=1x+b

4=1+b

3=b

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Standard Error from a Formula and a Bootstrap Distribution Sample A has a count of 30 successes with and Sample B has a count of

tia_tia [17]

Answer:

Using a formula, the standard error is: 0.052

Using bootstrap, the standard error is: 0.050

Comparison:

The calculated standard error using the formula is greater than the standard error using bootstrap

Step-by-step explanation:

Given

Sample A Sample B

$x_A = 30$ $x_B = 50$

$n_A = 100$ $n_B =250$

Solving (a): Standard error using formula

First, calculate the proportion of A

$p_A = \frac{x_A}{n_A}$

$p_A = \frac{30}{100}$

$p_A = 0.30$

The proportion of B

$p_B = \frac{x_B}{n_B}$

$p_B = \frac{50}{250}$

$p_B = 0.20$

The standard error is:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * (1 - 0.30)}{100} + \frac{0.20* (1 - 0.20)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.30 * 0.70}{100} + \frac{0.20* 0.80}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.21}{100} + \frac{0.16}{250}}$

$SE_{p_A-p_B} = \sqrt{0.0021+ 0.00064}$

$SE_{p_A-p_B} = \sqrt{0.00274}$

$SE_{p_A-p_B} = 0.052$

Solving (a): Standard error using bootstrapping.

Following the below steps.

Open Statkey
Under Randomization Hypothesis Tests, select Test for Difference in Proportions
Click on Edit data, enter the appropriate data
Click on ok to generate samples
Click on Generate 1000 samples ---- <em>see attachment for the generated data</em>

From the randomization sample, we have:

Sample A Sample B

$x_A = 23$ $x_B = 57$

$n_A = 100$ $n_B =250$

$p_A = 0.230$ $p_A = 0.228$

So, we have:

$SE_{p_A-p_B} = \sqrt{\frac{p_A * (1 - p_A)}{n_A} + \frac{p_A * (1 - p_B)}{n_B}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.23 * (1 - 0.23)}{100} + \frac{0.228* (1 - 0.228)}{250}}$

$SE_{p_A-p_B} = \sqrt{\frac{0.1771}{100} + \frac{0.176016}{250}}$

$SE_{p_A-p_B} = \sqrt{0.001771 + 0.000704064}$

$SE_{p_A-p_B} = \sqrt{0.002475064}$

$SE_{p_A-p_B} = 0.050$

5 0

3 years ago

If m 1 = 90°, what is m?

Setler79 [48]

Perpendicular

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7 0

3 years ago

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gulaghasi [49]

What is the X in the problem

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3 years ago

A dilation with a scale factor of 1/3 is a reduction.

Natasha_Volkova [10]

That's true.
That will make the thing a third of its original size.

8 0

3 years ago

URGENT!!! Find the rectangular coordinates of the point with the polar coordinates.

abruzzese [7]

we have that

(r, ∅)----------> (-7, 5 pi/3)

we know that

5 pi/3--------> 300°-----------> -60°

To convert polar cordinates in rectangular one with use the following formula:

x=r*cos ∅------> x=-7*cos -60°-------> x=-7*(1/2)------> x=-7/2

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the answer is the option

D) ordered pair negative 7 divided by 2 comma 7 square root 3 divided by 2

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3 years ago