Answer: RNA polymerase II hope this helps if not comment back and I’ll reply
Hello!
I will need a image to properly answer this question.
Thanks!~
Answer: 50% ErWw (wild-type traits) and 50% rrww (red eyes, white-banded wings)
To solve this, we need to analyze step by step all the data they give us.
First, they told you about two homozygous traits that are recessive in this kind of animal, Red eyes and withe-banded wings.
We'll assign the names rr and ww (lower because they are recessive)
You know the dominant traits are wild type and all are in the same chromosome.
EE will be normal eyes, and WW will be normal wings.
If you cross this F0, rrww x EERR all the offspring are ErWw.
Crossing F1 with red eyes, with-banded wing you have to draw a Punnte square with ErWw x rrww and the ofsspring posibilities you'll find are 50% ErWw (wild-type traits) and 50% rrww (red eyes, white-banded wings)
