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What is the circumference of a circular park with a radius of 100 meters? (Round your answer to the nearest tenth.)

Scilla [17]

Radius = 100m
Circumference of a circle = 2πr
= 2 × π× 100
=628.31m

7 0

3 years ago

Read 2 more answers

How can you solve an equation that has variables on both sides?

Sindrei [870]

Answer:

After simplifying, the first step in solving an equation with a variable on both sides is to get the variable on one side. This is done by reversing the addition or subtraction of one of the terms with the variable.

Step-by-step explanation:

8 0

3 years ago

2/3x − 1/5x = x −1 equals what? I'm confused on this

Galina-37 [17]

Answer:

x=15/8

Step-by-step explanation:

8 0

3 years ago

The world population was 2560 million people in 1950 and 3040 million in 1960 and can be modeled by the function p(t) 2560e0.017

almond37 [142]

Answer:

Step-by-step explanation:

The average rate of change is the slope. However, since this is not a linear function but an exponential one, we cannot determine the slope of the function, only the slope of the secant line that connects the x-values of 4 and 8. In order to do that we need to find the corresponding y-coordinate that goes with each of those x-values and plug them into the slope function. What we will get is a very loose interpretation of the rate of change of population, but that's all we have short of using calculus. It would be a closer estimation if we looked at x values of 4 and 5, or eve 4 ad 4.5. But that's not what we're being asked. So let's get to it.

Sub first 4 in for x and then 8, to get each y value:

$P(4)=2560e^{(.017185)(4)}$ to get that P(4) = 2742.16

$P(8)=2560e^{(.017185)(8)}$ to get that P(8) = 2937.29

The coordinates for these are (4, 2742.16) and (8, 2937.29)

Plug into the slope formula:

$m=\frac{2937.29-2742.16}{8-4}$ which gives you, in decimal form rounded to the nearest hundredth,

48.78 million.

The interpretation of this value in our situation is that between 1954 and 1958 the population increased 48.78 million people per year.

5 0

3 years ago

Prove diagonals of a rhombus are perpendicular

Lisa [10]

Answer:

A rhombus is a parallelogram with four congruent sides.

So, all sides of rhombus ABCD are congruent.

i.e, $\overline{JM} \cong \overline{JK} \cong \overline{KL}\cong \overline{LM}$

Also, we know that the diagonals of a parallelogram bisect each other.

Since a rhombus is a parallelogram.

By property of rhombus , if point N is the intersection of the diagonals as shown in the figure, then

$\overline{MN} \cong \overline{NK}$ .....[1]

$\overline{JN} \cong \overline{NL}$

In ΔJNM and ΔJNK

$\overline{MN} \cong \overline{NK}$ [side] [by (1)]

$\overline{JM} \cong \overline{JK}$ [side] [Given]

By reflexive property states that a segment is congruent to itself:

$\overline{JN} \cong \overline{JN}$ [Side] [Reflexive Property]

SSS(Side-Side-Side) postulates states that if three sides of one triangle are congruent to three sides of another triangle, then the two triangles are congruent.

then by SSS congruence,

$\triangle JNM \cong \triangle JNK$