Answer:
(21 + 11)2 = 64
So, I don't think teachers do this, but this is my way of doing it
Okay, so first, I divided 64 by 2 :
64 ÷ 2 = 32
Then, I subtracted 11 from 32:
21
Now, to check, just do the problem :
(21 + 11)2 = 64
32 * 2 = 64
First solve for x in the first equation. So you'll have to substitute,
5(3x-7)=20
15x-35=20
Then add 35 to both sides.
15x=55
Divide 55 by 15.
So x = 3.66...
Then plug in 3.7 for x in 6x-8
6(3.7)-8
Its approximately 14.2
Answer:
w is greater than or equal to 358
Answer:
B 71 & 71
Step-by-step explanation:
OP is an angle bisector
Answer:
3. 
2<em>C.</em> 
2<em>B.</em> 
2<em>A.</em> 
1. ![\displaystyle Set-Builder\:Notation: [x|7, 0 ≠ x] \\ Interval\:Notation: (-∞, 0) ∪ (0, 7) ∪ (7, ∞)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20Set-Builder%5C%3ANotation%3A%20%5Bx%7C7%2C%200%20%E2%89%A0%20x%5D%20%5C%5C%20Interval%5C%3ANotation%3A%20%28-%E2%88%9E%2C%200%29%20%E2%88%AA%20%280%2C%207%29%20%E2%88%AA%20%287%2C%20%E2%88%9E%29)
Step-by-step explanation:
3. <em>See</em><em> </em><em>above</em>.
2<em>C</em>. The keyword is ratio, which signifies division, so you would choose "III.".
2<em>B</em>. The keyword is percent, which signifies multiplication of a ratio by 100, so you would choose "I.".
2<em>A</em>. The keyword is total, which signifies addition, so you would choose "II.".
1. Base this off of the denominator. Knowing that the denominator CANNOT be zero, you will get this:
![\displaystyle x^2 - 7x \\ x[x - 7] = 0; 7, 0 = x \\ \\ Set-Builder\:Notation: [x|7, 0 ≠ x] \\ Interval\:Notation: (-∞, 0) ∪ (0, 7) ∪ (7, ∞)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20x%5E2%20-%207x%20%5C%5C%20x%5Bx%20-%207%5D%20%3D%200%3B%207%2C%200%20%3D%20x%20%5C%5C%20%5C%5C%20Set-Builder%5C%3ANotation%3A%20%5Bx%7C7%2C%200%20%E2%89%A0%20x%5D%20%5C%5C%20Interval%5C%3ANotation%3A%20%28-%E2%88%9E%2C%200%29%20%E2%88%AA%20%280%2C%207%29%20%E2%88%AA%20%287%2C%20%E2%88%9E%29)
I am joyous to assist you anytime.