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Nataliya [291]
3 years ago
12

Line j. y=

Mathematics
1 answer:
Helga [31]3 years ago
4 0

Answer:

the answer is c and of course the other answers are stupid u have wasted my precious time toodles!

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What is the value of -8(17-12)/-2(8-(-2))<br> A. -4<br> B. -2<br> C. 2 <br> D.4
Murljashka [212]

Answer:

C. 2

Step-by-step explanation:

-8*17=-136

-8*-12=96

-136+96=-40

-2*8=-16

-2*2=-4

-16-4=-20

-40/-20=2

7 0
3 years ago
What is 24.316 rounded to the nearest tenth
Marizza181 [45]
The correct answer is 24.3
7 0
4 years ago
Read 2 more answers
Which of the following are true about the graph of f(x)=-4x^2?
MrMuchimi

Answer:

the statements that are true are a & d

6 0
3 years ago
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Need help on the blanks. Pretty lost atm
nlexa [21]

Answer:

  • -108.26
  • -108.13
  • -108.052
  • -108.026
  • -108

Step-by-step explanation:

A graphing calculator or spreadsheet is useful for making the repeated function evaluations required.

The average velocity on the interval [a,b] will be ...

  v avg = (y(b) - y(a))/(b-a)

Here, all the intervals start at a=3, so the average velocity for the given values of t will be ...

  v avg = (y(3+t) -y(3))/((3+t) -3) = (y(3+t) -y(3))/t

This can be computed for each of the t-values given. The results are shown in the attached table.

__

We note that the fractional part of the velocity gets smaller in proportion to t getting smaller. We expect it to go to 0 when t goes to 0.

The estimated instantaneous velocity is -108 ft/s.

_____

We can simplify the average velocity equation to ...

  v avg = ((48(3+t) -26(t+3)^2) -(48(t+3) -26(3)^2)) / t

  = (48t -26(t^2 +6t))/t

  = 48 -26t -156

<em>   v avg = -108 -26t</em>

Then the average velocity at t=0 is -108.

5 0
4 years ago
The pie chart shows the information about the favourite ice creme flavour of each student in a schcool.There are 720 students at
Novay_Z [31]

Answer:

there would be many diffrent answers

Step-by-step explanation:

provide the full question, i can deduct that there are many ice cream flavors.

6 0
3 years ago
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