Ask question

Ask question

All categories

3 years ago

13

7,14,8,16,10,20,14 what is the rule

1 answer:

Yanka [14]3 years ago

3 0

I think it would just be (if 7 is x and 14 is y like a table where every 2 are a pair) 2x so the next number in the sequence would be 28

You might be interested in

PLS HELP!!! i feel like it’s probably easy i’m just a little confused

Katen [24]

Answer:

5

Step-by-step explanation:

It's an equilateral triangle

5 0

3 years ago

Read 2 more answers

Simplify the expression given below. 1/2x2-4x

stepan [7]

The answer is :

1 - 4x

5 0

3 years ago

HELLLLP (will mark brainiest)

Zigmanuir [339]

Answer:

We put the value of the x in the formula

${4 \times }(6)^{2} - 7 \times 6 + 12$

f(6)=

$4 \times 36 - 7 \times 6 + 12 = 144 - 42 + 12 = 102 + 12 = 114$

Step-by-step explanation:

Than solve equation.

6 0

3 years ago

Read 2 more answers

A swimming pool is represented on a coordinate grid with the following vertices: Vertex A is at (−2,−3) . Vertex B is at (−2,

Semmy [17]

Answer:

26 yards.

Step-by-step explanation:

We can find the distance walked by Jared by finding the distances between each of the given vertex of swimming pool. We will use distance formula to find the distances between each vertex.

$\text{Distance}=\sqrt{(x_2-x_1)^{2}+(y_2-y_1)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(-2--2)^{2}+(-3-5)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(-2+2)^{2}+(-8)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{(0)^{2}+(-8)^{2}}$

$\text{Distance between vertex A and vertex B}=\sqrt{64}=8$

Now let us find distance between vertex B and vertex C.

$\text{Distance between vertex B and vertex C}=\sqrt{(-2-3)^{2}+(5-5)^{2}}$

$\text{Distance between vertex B and vertex C}=\sqrt{(-5)^{2}+(0)^{2}}$

$\text{Distance between vertex B and vertex C}=\sqrt{25}=5$

Now let us find distance between vertex C and vertex D.

$\text{Distance between vertex C and vertex D}=\sqrt{(3-3)^{2}+(5--3)^{2}}$

$\text{Distance between vertex C and vertex D}=\sqrt{(0)^{2}+(5+3)^{2}}$

$\text{Distance between vertex C and vertex D}=\sqrt{64}=8$

Now let us find distance between vertex D and vertex A.

$\text{Distance between vertex D and vertex A}=\sqrt{(3--2)^{2}+(-3--3)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{(3+2)^{2}+(-3+3)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{(5)^{2}+(0)^{2}}$

$\text{Distance between vertex D and vertex A}=\sqrt{25}=5$

Now let us add all these distances to find the total distance walked by Jared.

$\text{Total distance walked by Jared}=8+5+8+5$

$\text{Total distance walked by Jared}=26$

Since we have been given that one unit on the grid equals 1 yard, therefore, Jared walked a distance equal to 26 yards.

3 0

3 years ago

How many ounces of milk would you need for 5 ounces of flour?

monitta

Answer:

5 ounces of milk

Step-by-step explanation:

4 0

2 years ago