<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
c
Step-by-step explanation: all you have to do is work it out
Answer:
p = 8/25
Step-by-step explanation:
500 - 340 = 160 girls
p = 160/500
p = 8/25
Answer:
1
Step-by-step explanation:
The coefficient is the number being multiplied with the variable, since p is simply just p, it's just being multiplied by 1.
What shape is it? i can’t help if i don’t know the shape
