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Fudgin [204]
3 years ago
13

A granite monument has a volume of 25,365.4 cm3. The density of granite is 2.7 g/cm3. Use this information to calculate the mass

of the monument to the nearest tenth.
The mass of the granite monument is
g
Mathematics
1 answer:
Vaselesa [24]3 years ago
6 0

Answer:

<h3>The answer is 68,486.58 g</h3>

Step-by-step explanation:

The mass of a substance when given the density and volume can be found by using the formula

<h3>mass = Density × volume</h3>

From the question

volume of granite monument =

25,365.4 cm³

density = 2.7 g/cm³

The mass of the granite monument is

mass = 25,365.4 × 2.7

We have the final answer as

<h3>68,486.58 g</h3>

Hope this helps you

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MatroZZZ [7]
The answer to this question is 27/28
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3 years ago
a chef uses 4 3/4 cups of broth for 10 servings of soup.how much broth is is one serving . let x represent amount. 4 3/4/10 =x/1
enyata [817]
Let's firstly convert the mixed fraction to "improper" and then proceed,

\bf \begin{array}{ccll}&#10;\stackrel{broth}{cups}&servings\\&#10;\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\&#10;4\frac{3}{4}&10\\\\&#10;x&1&#10;\end{array}\implies \cfrac{\quad \stackrel{mixed}{4\frac{3}{4}}\quad }{x}=\cfrac{10}{1}\implies \cfrac{\quad \frac{4\cdot 4+3}{4}\quad }{x}=\cfrac{10}{1}

\bf \cfrac{\quad \stackrel{improper}{\frac{19}{4}}\quad }{x}=\cfrac{10}{1}\implies \cfrac{\quad \frac{19}{4}\quad }{\frac{x}{1}}=\cfrac{10}{1}\implies \cfrac{19}{4}\cdot \cfrac{1}{x}=\cfrac{10}{1}\implies \cfrac{19}{4x}=\cfrac{10}{1}&#10;\\\\\\&#10;19=40x\implies \cfrac{19}{40}=x
6 0
3 years ago
Hello there
Dafna1 [17]

Answer:

20

Step-by-step explanation:

2/3 want to go

If there are 30 people, we can find our answer pretty easily as 30 is 10 times more than 3.

2/3 = 20/30

So 20 people would like to go :O

Hope this helps, have a nice day :))

6 0
2 years ago
Read 2 more answers
Please helppppppp ASAP
pshichka [43]

Answer:

I think it is C

Step-by-step explanation:

5 0
3 years ago
Several years​ ago, 38​% of parents who had children in grades​ K-12 were satisfied with the quality of education the students r
Colt1911 [192]

Answer:

0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995

0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

Step-by-step explanation:

For this case we are interesting in the parameter of the true proportion of people satisfied with the quality of education the students receive

The confidence level is given 95%, the significance level would be given by \alpha=1-0.95=0.05 and \alpha/2 =0.025. And the critical values are:

z_{\alpha/2}=-1.96, z_{1-\alpha/2}=1.96

The estimated proportion of people satisfied with the quality of education the students receive is given by:

\hat p =\frac{499}{1165}= 0.428

The confidence interval for the proportion if interest is given by the following formula:  

\hat p \pm z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}

And replacing the info given we got:

0.428 - 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.3995

0.428 + 1.96\sqrt{\frac{0.428(1-0.428)}{1165}}=0.4564

We are confident that the true proportion of people satisfied with the quality of education the students receive is between (0.3995, 0.4564), since the lower value for this confidence level is higher than 0.38 we have enough evidence to conclude that the parents' attitudes toward the quality of education have changed.

8 0
3 years ago
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