simplify the following polynomial expression.
B%28-2x%5E%7B3%7D%20%2B3x%5E%7B2%7D%20-7x%2B9%29-%285x%2B3%29%284x%5E%7B2%7D%20%2Bx-1%29" id="TexFormula1" title="(5x^{3} +4x^{2} +6x-3)+(-2x^{3} +3x^{2} -7x+9)-(5x+3)(4x^{2} +x-1)" alt="(5x^{3} +4x^{2} +6x-3)+(-2x^{3} +3x^{2} -7x+9)-(5x+3)(4x^{2} +x-1)" align="absmiddle" class="latex-formula">
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Answer:
The doctor's dosage was not appropriate.
The right dosage is from 56.625 mg to 113.25 mg of Antibiotic to be given every 6 hour for the child with weight 25 lbs.
Step-by-step explanation:
It is given that 20 to 40 mg/kg/day is the recommended dosage.
Now, the doctor's order is 150 mg of antibiotic to be given every 6 hours. And my child weighs 25 lbs.
Now, 1 lb is equivalent to 0.453 kg.
So, my child's weight is (25 × 0.453) = 11.325 kg.
So, the doctor's order is 150 mg of antibiotic to be given every 6 hours for a child of weight 11.325 kg.
Hence, the dosage is [(150 × 4) ÷ 11.325] = 52.98 mg/kg/day.
So, this is not within the limit of 20 to 40 mg/kg/day.
Therefore, the doctor's dosage was not appropriate.
Now, let the appropriate dosage is x mg per every 6 hours for a child with weight 25 lbs i.e. 11.325 kg.
So,
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So, the right dosage is from 56.625 mg to 113.25 mg of antibiotic to be given every 6 hours for the child with weight 25 lbs. (Answer)