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3 years ago

9

Question is 15 points

2 answers:

Korvikt [17]3 years ago

4 0

I think the answer is B

algol133 years ago

4 0

I'm assuming 0.766 is just sin 58.

sin of an angle is the opposite measure divided by the hypotenuse.

sin 58 = x/12, your second option

To keep going and solve, you would multiply both sides by 12 to isolate the variable x and cancel out 12 on the right side, leaving you with x = 12(sin 58)

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Find the total surface area.

Ede4ka [16]

Hey love! <3

Answer:

The right answer is A = 49.6 π ft^2

Step-by-step explanation:

<em><u>(Let pi = 3.1415926535898)</u></em>

<em>The formula for calculating the surface area of a cylinder is A=2πrh+2πr^2</em>

<em>So if r = 4 ft</em>

<em>and h = 2.2 ft</em>

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<em>Once we've plugged in our formulas our final surface area is A =</em><em> 49.6 π ft2</em>

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8 0

3 years ago

Read 2 more answers

Solve the system by elimination.(show your work)

PilotLPTM [1.2K]

Answer:

x = 1 , y = 1 , z = 0

Step-by-step explanation by elimination:

Solve the following system:

{-2 x + 2 y + 3 z = 0 | (equation 1)

-2 x - y + z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Subtract equation 1 from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x - 3 y - 2 z = -3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

2 x + 3 y + 3 z = 5 | (equation 3)

Add equation 1 to equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+3 y + 2 z = 3 | (equation 2)

0 x+5 y + 6 z = 5 | (equation 3)

Swap equation 2 with equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+3 y + 2 z = 3 | (equation 3)

Subtract 3/5 × (equation 2) from equation 3:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - (8 z)/5 = 0 | (equation 3)

Multiply equation 3 by 5/8:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y - z = 0 | (equation 3)

Multiply equation 3 by -1:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y + 6 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 6 × (equation 3) from equation 2:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+5 y+0 z = 5 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 2 by 5:

{-(2 x) + 2 y + 3 z = 0 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 2 × (equation 2) from equation 1:

{-(2 x) + 0 y+3 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Subtract 3 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = -2 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = 1 | (equation 1)

0 x+y+0 z = 1 | (equation 2)

0 x+0 y+z = 0 | (equation 3)

Collect results:

Answer: {x = 1 , y = 1 , z = 0

6 0

3 years ago

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MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!

Blizzard [7]

ive forgotten the method

4 0

3 years ago

Please help. Thanks. Work is due tomorrow. Thanks

eimsori [14]

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7 0

3 years ago

I don't understand this problem...like how to combine the k terms or how to get the answer.

creativ13 [48]

Answer:

-6 k +5

Step-by-step explanation:

-2k -4k +5

Think of k is apples

-2 apples -4 apples

-6 apples

-6 k +5

3 0

3 years ago

Read 2 more answers