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3 years ago

What is the solution to the inequality -.4x-1.2 >.8

Mathematics

1 answer:

Mademuasel [1]3 years ago

4 0

Answer:

x < -1

Step-by-step explanation:

Solve -.4x-1.2 >.8 for x.

Start by adding 1.2 to both sides, to isolate -0.4 x:

-0.4x > 0.4

Divide both sides by -0.4, remembering the reverse the direction of the inequality sign:

x < -1

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Our club has 25 members, and wishes to pick a president, secretary, and treasurer. In how many ways can we choose the officers,

Rus_ich [418]

Answer:

13800

Step-by-step explanation:

The order of the members is important (because each selected member will receive a different position), thus we then need to use the definition of permutation.

There are 25 members, of which 3 are selected.

$\begin{array}{l}n=25 \\r=3\\end{array}$

Evaluate the definition of a combination:

$P(25,3)=\frac{25 !}{(25-3) !}=\frac{25 !}{22 !}=25 \cdot 24 \cdot 23=13800$

8 0

3 years ago

What would 9c-6+c be as an equivalent expression

pshichka [43]

-6+10c
I think, reorder the terms: -6+9c+c= -6+10c

8 0

3 years ago

PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS

Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

$a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\$

With respect to reference angle A, we have:

opposite side = a = 4
adjacent side = b = $\sqrt{33}$
hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

$\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\$

Then cosine which is adjacent over hypotenuse

$\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\$

Tangent is the ratio of opposite over adjacent

$\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\$

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

cosecant, abbreviated as csc, is the reciprocal of sine
secant, abbreviated as sec, is the reciprocal of cosine
cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

$\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{ ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

------------------------------------------------------

Summary:

The missing side is $b = \sqrt{33}$

The 6 trig functions have these results

$\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\$

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0

2 years ago

4cos(10x)+2=2<br><br> What would this equal in Degrees??

Ipatiy [6.2K]

Answer:

Simplifying

4cos(10x) + 2 = 2

Remove parenthesis around (10x)

4cos * 10x + 2 = 2

Reorder the terms for easier multiplication:

4 * 10cos * x + 2 = 2

Multiply 4 * 10

40cos * x + 2 = 2

Multiply cos * x

40cosx + 2 = 2

Reorder the terms:

2 + 40cosx = 2

Add '-2' to each side of the equation.

2 + -2 + 40cosx = 2 + -2

Combine like terms: 2 + -2 = 0

0 + 40cosx = 2 + -2

40cosx = 2 + -2

Combine like terms: 2 + -2 = 0

40cosx = 0

Solving

40cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '40'.

cosx = 0.0

Simplifying

cosx = 0.0

The solution to this equation could not be determined.

Step-by-step explanation:

7 0

4 years ago

If there were 310 million people in the United States, what was the daily consumption rate in barrels per person in the United S

bija089 [108]

The daily consumption rate in the United States will be 10 barrels per person.

Your question is incomplete as you didn't provide the total barrels, therefore, an overview of the answer will be given. In their case, let's assume that the total barrels is given as 3.1 billion.

Therefore, the barrels per person will be:

= Total barrels / Population

= 3.1 billion / 310 million

= 10 barrels per person.

In conclusion, the correct option is 10 barrels per person.

Read related link on:

brainly.com/question/25261899

7 0

3 years ago