3 years ago

PLEASE HELP DUE IN 5 MINUTS

Mathematics

1 answer:

Serhud [2]3 years ago

3 0

Answer:

nice

Step-by-step explanation:

nice nice nice nice nice

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If the rate of decay is 1% per year, the number of grams present after 12 years is found from:
$52\times(0.99)^{12}=46\ grams$
An alternative solution can use the following equation:
$N(t)= N_{0} e^{-\lambda t}$
Plugging in given values, we get:
$N=52\times e^{-0.01\times t}=46\ grams$

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