Answer:
normally i would but i think it will be better if you did it yourself. i mean you can always use a calculator
explanation:
I hope this helps you!
1) Find the derivative
and
.
2) The equation of the tangent line is
, so at point (2,6):
and
-the equation of the tangent line at point (2,6).
There are 3 methods to solve this. elimination substitution and graphing but i am going to use the elimination method.
x+2y=17
<u> x-y =2
</u> 0+3y =15 ( subtracted down to eliminate the x)( x-x=0, 2y-(-y)=3y, and 17-2=15)
3y=15 (divide both sides by 3 to solve for y)
y=5
<u>substitute the y=5 in any of the above equations and solve for x
ie... ( </u>meaning where you find y in the equation, u replace it with a 5)
it will be easier to solve for x in (x-y=2) so i will use that one.
x-(5)=2 ( add 5 on both sides to solve for x)
x=7
Answer:
Step-by-step explanation: B. SSS because it shows us three sides ,C.RHS because it has a right angle, d. AAS because it shows us two sides and a non included side, e. RHS because it has a right angle, f. AAS because it has two angles and non included side.
Add the ratios together:
5 + 2 + 1 = 8
Divide the length of NQ by that:
24/8 = 3
Multiply the ratio of NO by that/l
The ratio of NO is 5, 5 x 3 = 15
NO = 15
