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swat32
3 years ago
10

Plz help GET LOTS OF POINTS!!!!!!

Mathematics
1 answer:
RideAnS [48]3 years ago
6 0

Answer:

slope = 3/2

y intercept = 2

y = 3/2x + 2

Step-by-step explanation:

to find the slope you will you (y₂-y₁) ÷ (x₂-x₁)

(11-5) ÷ (6-2) =

6 ÷ 4 = 3/2

slope = 3/2

to find the y intercept you with use the slope intercept formula (y = mx+ b) and use one point given for x and y

for the example im going to use the point (2,5)

5 = 3/2 (2) + b

5 = 3 + b

subtract three from both sides to find b (y-intercept)

b = 2

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damaskus [11]

Answer: x=3/5

Step-by-step explanation:

4 0
3 years ago
Solve the formula for the indicated variable <br> A=1/2bh solve for h
vfiekz [6]

Answer:

h=A*2b

Step-by-step explanation:

A=1/2bh

1/2bh=A

1/2bh÷1/2bh=A÷1/2bh (the 1/2b will cancel with the 1/2b on the left leaving h)

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7 0
4 years ago
I need help please and explain your answer it’s number 4
Brums [2.3K]

Answer:

29

Step-by-step explanation:

Well "value" of 3x^2 - 7x + 9 when x = 4 is just x plugged into the expression

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3 * 16 - 28 + 9

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8 0
2 years ago
If both slopes are undefined are they parallel?
SCORPION-xisa [38]

Answer:

If the slopes of the lines are both zero, the lines are horizontal and are parallel by definition. Since the slopes of vertical lines are undefined and not considered equal, vertical lines will not be considered.

I hope this helps you :)

8 0
2 years ago
Please help
ASHA 777 [7]

Answer:

(-6,4)

Step-by-step explanation:

The equations are:

x^2+4y^2=100\\4y-x^2=-20

Solving for x^2 of the 2nd equation and putting that in place of x^2 in the 2nd equation we have:

4y-x^2=-20\\x^2=4y+20\\-------\\x^2+4y^2=100\\4y+20+4y^2=100

Now we can solve for y:

4y+20+4y^2=100\\4y^2+4y-80=0\\y^2+y-20=0\\(y+5)(y-4)=0\\y=4,-5

So plugging in y = 4 into an equation and solving for x, we have:

x^2=4y+20\\x=+-\sqrt{4y+20} \\x=+-\sqrt{4(4)+20} \\x=+-\sqrt{36} \\x=6,-6

So y = 4 corresponds to x = 6 & x = -6

The pairs would be

(6,4) & (-6,4)

<u><em>we see that (-6,4) falls in the 2nd quadrant, thus this is the solution we are looking for.</em></u>

5 0
3 years ago
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