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Sveta_85 [38]
3 years ago
14

22(x)=44 what is the answer to this problem?

Mathematics
2 answers:
yawa3891 [41]3 years ago
7 0

 x = 2

22x = 44

22x/ 22 = 44 / 22         -Divide both sides by 22

x = 2

Hope this helps! If so, please mark brainliest!

RSB [31]3 years ago
4 0
<h3>Hey there! </h3>

22x= 44

<h2>The easier method in order to solve for the value of x is to DIVIDE by 22 on EACH OF YOUR SIDES </h2><h3>\frac{22x}{22} = \frac{44}{22}</h3><h3>Cancel out: \frac{22x}{22} because that gives you the result of 1</h3><h3>Keep: \frac{44}{22} because it gives you the value of x</h3><h3>\frac{44}{22} = 2</h3><h3>Therefore your answer (also know as "the value of x" ) would most likely be: 2</h3><h3>Good luck on your assignment and enjoy your day! </h3><h3>~LoveYourselfFirst:)</h3>
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Step-by-step explanation:

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Any help with an explanation would be appreciated!
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Problem 1

We'll use the product rule to say

h(x) = f(x)*g(x)

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

Then plug in x = 2 and use the table to fill in the rest

h ' (x) = f ' (x)*g(x) + f(x)*g ' (x)

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h ' (2) = 2*3 + 2*4

h ' (2) = 6 + 8

h ' (2) = 14

<h3>Answer: 14</h3>

============================================================

Problem 2

Now we'll use the quotient rule

h(x) = \frac{f(x)}{g(x)}\\\\h'(x) = \frac{f'(x)*g(x)-f(x)*g'(x)}{(g(x))^2}\\\\h'(2) = \frac{f'(2)*g(2)-f(2)*g'(2)}{(g(2))^2}\\\\h'(2) = \frac{2*3-2*4}{(3)^2}\\\\h'(2) = \frac{6-8}{9}\\\\h'(2) = -\frac{2}{9}\\\\

<h3>Answer:  -2/9</h3>

============================================================

Problem 3

Use the chain rule

h(x) = f(g(x))\\\\h'(x) = f'(g(x))*g'(x)\\\\h'(2) = f'(g(2))*g'(2)\\\\h'(2) = f'(3)*g'(2)\\\\h'(2) = 3*4\\\\h'(2) = 12\\\\

<h3>Answer:  12</h3>
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3 years ago
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NNADVOKAT [17]

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4 0
3 years ago
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