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Aleonysh [2.5K]
3 years ago
12

Change 48 out of 60 to a percentage

Mathematics
2 answers:
velikii [3]3 years ago
8 0

Answer:

80%

Convert fraction (ratio) 48 / 60 Answer: 80%

Softa [21]3 years ago
5 0
48/60 x 100%

= 4/5 x 100%

= 80%

Hope it helps!
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In triangle ABC, line A.B.=CB Angle ABC equals 4X -3, and angle CAB equals X -3, what is angle ACB
Soloha48 [4]

Answer:

∠ACB = 28.5

Step-by-step explanation:

In triangle ABC,

angle CAB = x-3

angle ABC = 4X-3

It is also given that AB=CB

We know that if two sides of any triangle are equal then corresponding sides must also be equal.

Hence

angle ACB = angle CAB

angle ACB = x-3    {Given that angle CAB = x-3 }

We know that sum of all three angles of a triangle is 180 degree so let's add given angles

angle ACB + angle CAB + angle ABC = 180

(x-3) + (x-3) + (4x-3) = 180

x-3 + x-3 + 4x-3 = 180

6x-9 = 180

6x = 180+9

6x = 189

x = 189/9

x= 31.5

Now plug value of x into

angle ACB = x-3 = 31.5-3 = 28.5

Hence final answer is

∠ACB = 28.5


3 0
3 years ago
Roberto studied 3/5 hour every day for 7 days. How many hours did Roberto study in 7 days?
slavikrds [6]
I believe it would be 4 1/5 hours
5 0
3 years ago
Read 2 more answers
Which of the following is the maximum value of the equation y = −x2 − x + 6?
Ratling [72]

Step-by-step explanation:

f(x) = y= -x²-x+6

When y is max, f'(x) = 0

f'(x) = -2x-1

Equating to 0,

-2x-1= 0

x= -1/2

Put the value of x in f(x)

y = -(-1/2)² -(-1/2) +6

= -1/4+1/2+6

= 6+1/2

y= 13/2

4 0
2 years ago
What does it mean when they say what is the mean of a data set?
astra-53 [7]

Answer:

the mean of a set is the average of the numbers in that set. How you get the mean is you add up all the numbers then you divide by how many numbers are in the set.

Step-by-step explanation:

example is 1,2,3,4,5,6,7

the mean of this set is 4

3 0
3 years ago
Read 2 more answers
Bruce reads 3fourths hour each night.how long will he read in 4 nights
OlgaM077 [116]
3 fourths of an hour is : (3/4)
(3/4)*4=3 hours

hope this helps!
5 0
3 years ago
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