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3 years ago

Change 48 out of 60 to a percentage

Mathematics

2 answers:

velikii [3]3 years ago

8 0

Answer:

80%

Convert fraction (ratio) 48 / 60 Answer: 80%

Softa [21]3 years ago

5 0

48/60 x 100%

= 4/5 x 100%

= 80%

Hope it helps!

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Functions A,B and C are linear functions. Some values of function A are shown in the table. Function B has y-intercept of (3,0)

cricket20 [7]

Answer:

In order of increasing slope:

B: y = 0

A: y = 2x-3

C: y = 3x+1

Step-by-step explanation:

(3,3), (5,7), and (6,9) are points on line A.

Use the coordinates of two of the points to find the slope of A.

Δy =7-9 = -2

Δx =5-6 = -1

Slope = Δy/Δx = 2

Equation for line of slope 2 that passes through (3,3):

y-3 = 2(x-3)

y = 2x-3

(3,0) and (5,0) are points on line B. They are horizontally aligned, so the equation for line B is y=0. Slope = 0.

You were given the equation for C: y = 3x+1. Slope = 3

In order of increasing slope:

B: y = 0

A: y = 2x-3

C: y = 3x+1

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2 years ago

How many passwords of 5 characters (numbers or letters) can be created if repeats are allowed

alex41 [277]

Answer:

at least 290,000

Step-by-step explanation:

Why is this a question

4 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

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2 years ago

Is 50 a perfect square ? Explain your answer please

xeze [42]

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3 years ago

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Answer:

Step-by-step explanation:

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3 years ago

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