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3 years ago

Change 48 out of 60 to a percentage

Mathematics

2 answers:

velikii [3]3 years ago

8 0

Answer:

80%

Convert fraction (ratio) 48 / 60 Answer: 80%

Softa [21]3 years ago

5 0

48/60 x 100%

= 4/5 x 100%

= 80%

Hope it helps!

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a parallelogram has side lenghts 20 cm and 25 cm. the diagonal opposite the obtuse angle measures 38 cm. what is the measure of

Nady [450]

Step-by-step explanation:

1. draw the parallelogram with side 20cm and 25cm respectively and also the diagonal as well.

2.Clearly it forms a triangle in the parallelogram with three known lengths of side.

3.Using the cosine rule : c^2=b^2+c^2 -2bc cos c to find the obtuse angle.

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3 years ago

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Drag the tiles to the correct boxes to complete the pairs not all tiles will be used match each quadratic graph to its respectiv

ch4aika [34]

Answer:

Part 1) The function of the First graph is $f(x)=(x-3)(x+1)$

Part 2) The function of the Second graph is $f(x)=-2(x-1)(x+3)$

Part 3) The function of the Third graph is $f(x)=0.5(x-6)(x+2)$

See the attached figure

Step-by-step explanation:

we know that

The quadratic equation in factored form is equal to

$f(x)=a(x-c)(x-d)$

where

a is the leading coefficient

c and d are the roots or zeros of the function

Part 1) First graph

we know that

The solutions or zeros of the first graph are

x=-1 and x=3

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-3)(x+1)$

Find the value of the coefficient a

The vertex is equal to the point (1,-4)

substitute and solve for a

$-4=a(1-3)(1+1)$

$-4=a(-2)(2)$

$a=1$

therefore

The function is equal to

$f(x)=(x-3)(x+1)$

Part 2) Second graph

we know that

The solutions or zeros of the first graph are

x=-3 and x=1

The parabola open down, so the leading coefficient a is negative

The function is equal to

$f(x)=a(x-1)(x+3)$

Find the value of the coefficient a

The vertex is equal to the point (-1,8)

substitute and solve for a

$8=a(-1-1)(-1+3)$

$8=a(-2)(2)$

$a=-2$

therefore

The function is equal to

$f(x)=-2(x-1)(x+3)$

Part 3) Third graph

we know that

The solutions or zeros of the first graph are

x=-2 and x=6

The parabola open up, so the leading coefficient a is positive

The function is equal to

$f(x)=a(x-6)(x+2)$

Find the value of the coefficient a

The vertex is equal to the point (2,-8)

substitute and solve for a

$-8=a(2-6)(2+2)$

$-8=a(-4)(4)$

$a=0.5$

therefore

The function is equal to

$f(x)=0.5(x-6)(x+2)$

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4 years ago

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kipiarov [429]

A 42 24÷16 =1.5 1.5×28 =42 b i think its 78.4 im not sure

4 0

3 years ago

What is the general form of the equation for the given circle centered at O(0, 0)?

eduard

The general form of such an equation is
x^2 + y^2 = r^2 where r = radius

In this case r^2 = 4^2 + 5^2 = 41

So the required equation is x^2 ^ y^2 = 41

B

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3 years ago

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What is the greatest common factor of 3 and 13?

Lyrx [107]

Answer: 1

Step-by-step explanation:

In order to find GCF, take the prime factorization of 3 and 13.

3: 1*3 ==> Prime factorization of 3

13: 1*13 ==> Prime factorization of 3

The common factor is 1.

GCF of 13 and 3 is 1

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1 year ago

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