Hello!
This is a problem about the general solution of a differential equation.
What we can first do here is separate the variables so that we have the same variable for each side (ex. 
with the 
term and 
with the 
term).
Then, we can integrate using the power rule to get rid of the differentiating terms, remember to add the constant of integration, C, to at least one side of the resulting equation.
Then here, we just solve for and we have our general solution.
![y=\sqrt[3]{\frac{1}{2}x^2-x+C}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B%5Cfrac%7B1%7D%7B2%7Dx%5E2-x%2BC%7D)
We can see that answer choice D has an equivalent equation, so answer choice D is the correct answer.
Hope this helps!
Answer:
Back to your fraction 3/4, if you have 3 parts of 4, you have 3 25% slices which is 3 * 25% = 75%. Now that you have 3/4 as a percentage you simply have to covert the percent to a decimal. To do this you will just move the decimal 2 places to the left.
Step-by-step explanation:
mark me as the brainliest
To solve the first question, the angles J and K are perpendicular to each other, that means also that the angles are 90 degrees.
Apart from each other.
This is the total angle measure, that means the sum of the smaller angles must equal 90 degrees.
So the expression would be
2x - 9 + 27 = 90
2x + 18 = 90
2x = 90 - 18
2x = 72
X = 72/2 = 36 degrees.
For the second question since w and v are parallel that means the angles are equal to each other
Thus make the expressions and value equal to each other and solve for x
3x + 60 = 120
3x = 60
X = 20 degrees.
Answer:
-4
Step-by-step explanation:
plug in -2
-(-2)^2 = -4
