There is 100% of cats & dogs, 70% of dog and 30% of cats

2 answers:

8 0

Say you have 100 cats and dogs well 70 of them are dog and 30 are cats. out of the 70 dogs 50 drink water and the other 20 eat food but the 30 cats took half of the dogs food and water so you would divide 2 into the 50 to get how much water the cats took of food and you would divide 2 into the 20 to get what the cats took of food from the dogs. so it would be 50/2=25 water and 20/2=10 food and then add those two numbers together to get 35

vampirchik [111]3 years ago

5 0

Answer:

why is your account deleted

Step-by-step explanation:

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Let AA and BB be events such that P(A∩B)=1/73P(A∩B)=1/73, P(A~)=68/73P(A~)=68/73, P(B)=21/73P(B)=21/73. What is the probability

krok68 [10]

Answer:

$P(A \cup B) = \frac{5}{73} +\frac{21}{73} -\frac{1}{73}=\frac{25}{73}$

Step-by-step explanation:

Let A and B events. We have defined the probabilities for some events:

$P(A') =\frac{68}{73} , P(B) =\frac{21}{73} , P(A \cap B) =\frac{1}{73}$

Where A' represent the complement for the event A

The complement rule is a theorem that provides a connection between the probability of an event and the probability of the complement of the event. Lat A the event of interest and A' the complement. The rule is defined by: $P(A)+P(A') =1$