Answer:
540 ft^2.
Step-by-step explanation:
The area of the trapezoid = h/2 (10 + 18) = 14h.
By Pythagoras the height h = √(5^2 - 4^2) = 3.
So the area of the 2 trapezoidal bases = 2 * 14*3
= 84 ft^2.
Now we calculate the area of the four lateral rectangular sides:
= 10*12 + 18*12 + 2*5*12
= 456 ft^2.
Total area = 456 + 54
= 540 ft^2.
5x + 50 +x
= 5x*2( square ) + 50
Im a little confused here because there isn't enough information to go on or I might be reading it wrong.
If we had AB: BC: CD, we could easily have solved that problem. In order to combine these ratios, we need to have the same number for BC. We can create this number by finding LCM (Least Common Multiple) for 5 and 3, which is 15. Then, we can write ratios of AB:BC = 6:15 and BC:CD=15:20. Now, we can easily combine these ratios. AB:BC:CD = 6:15:20. Then, 6k+15k+20k = 82 and k=2 cm. And BC = 30 cm
First, a scale factor is the ratio of the corresponding sides in two similar geometric figures.
To find the scale factor:
1. Locate two corresponding sides (one on each figure).
2. Write the ratio of one length to the other.
And there you go! That's the scale figure from one figure to the other
Hope that helps and correct me if I'm wrong!
