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yulyashka [42]
3 years ago
13

Using side lengths only, could the triangles be similar? Triangle X Y Z. Side X Y is 1.5, X Z is 1, Z Y is 2. Triangle Q S R. Si

de Q R is 1, R S is 1.5, S Q is 0.5.
Mathematics
1 answer:
ruslelena [56]3 years ago
5 0

Answer:

  no

Step-by-step explanation:

In ∆XYZ, we can write the ratios of the sides from shortest to longest as ...

  y : z : x = 1 : 1.5 : 2 = 2 : 3 : 4

In ∆QSR, we can write the ratios of the side lengths from shortest to longest as ...

  r : s : q = 0.5 : 1 : 1.5 = 1 : 2 : 3

Based on side lengths only, the triangles cannot be similar.

__

<em>Additional note</em>

Even if shortest-to-longest side ratios were the same, the triangle naming is incorrect for them to be similar.

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Harlamova29_29 [7]

Answer:  Missing parts are,

In first blank,  AD\cong DC,

In second blank, SAS postulate

In third blank, CPCTC postulate

Step-by-step explanation:

Since, Here D is the mid point on the line segment AC.

And BD is a perpendicular to the line AC.

Therefore, In triangles ADB and CDB ( shown in figure)

AD\cong DC ( By the definition of mid point)

\angle BDA\cong \angle BDC ( right angles )

BD\cong BD ( reflexive)

Thus, By SAS ( side angle side )postulate,

\triangle ADB\cong \triangle CDB

So, by CPCTC( Corresponding parts of congruent triangles are congruent)

AB\cong CB

Now, By definition of congruent segment,

AB=CB

By definition of equidistant,

B is equally far from both A and C.




7 0
3 years ago
Read 2 more answers
What is the 11th term of the sequence<br> 1, 2, 4, 8, 16, ...?
iris [78.8K]

Answer:

1024

Step-by-step explanation:

16x2=32

32x2=64

64x2=128

128x2=256

256x2=512

512x2=1024

x= previous term multiplied by 2

hopefully this helps :)

5 0
3 years ago
A community group bought 30 tickets to an amusement park at a total cost of $810. They bought x students for $25 each and y adul
allsm [11]
A community group bought 30 tickets to an amusement park at a total cost of $810. They bought x student tickets for $25 each and y adult tickets for $30 each.
***
let x=number of student tickets bought
30-x=number of adult tickets bought
..

25x+30(30-x)=810
25x+900-30x=810
5x=90
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30-x=12
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8 0
3 years ago
I'm genuinely lost in any problems like this and my teachers are no help, I need help doing exponents in general, everything to
Stolb23 [73]

Answer:

See below.

Step-by-step explanation:

4)

So we have the expression:

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(ab)^n=a^n\cdot b^n

So:

=(-6)^2\cdot(n^{-3})^2

For the left, -6 squared is the same as -6 times -6. This equals positive 36.

For the right, we can use the power of a power property. The property says that:

(a^n)^k=a^{nk}

So:

(n^{-3})^2=n^{(-3)(2)}\\=n^{-6}

So, all together, we have:

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We have the expression:

-\frac{3x^0}{x^4}

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And that's the simplest we can do :)

Notes for 6)

We <em>can</em> put the x^4 to the numerator. Recall that when you put an exponent to opposite side, you put a negative. In other words:

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And vice versa:

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So, we can write the above as:

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However, traditionally, we want only positive exponents, so this wouldn't be correct.

4 0
3 years ago
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Divide 25/9 and you'll get the decimal 2.7 repeating boom decimal.
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