Let x = speed of the first car
the second car is 12 km slower so the seconds car speed is x-12
they each drove 2 hours so 1st car = 2x
2nd car = 2(x-12)
they drove 360 km
so you have 2x + 2(x-12) = 360
solve for x
2x+2(x-12) = 360
2x + 2x-24 = 360
4x-24 = 360
4x = 384
x = 384/4
x = 96
1st car drove at 96 km per hour
slower car drove at 96-12 = 84 km per hour
Answer:
60
Step-by-step explanation:
Cot is the same as 1/tan so:
By rearranging the equation, we get:
By taking the inverse tan, we get:
0
evaluate g(7) by substituting x = 7 into g(x
g(7) = (49-35-10)/2 = 4/2 = 2
now substitute x = 2 into f(x)
f(2) = √(4 - 48 + 144) = √0 = 0
(f ￮ g)(7) = 0
Answer:
Step-by-step explanation:
h = −16(x − 2)² + 72
= −16((x − 2)(x − 2)) + 72 expand the square (x - 2)² = (x - 2)(x - x)
= -16 ((x)(x) + (x)(-2) + (-2)(x) + (-2)(-2)) + 72
= -16 (x² + (-2x) + (-2x) + (4) ) + 72
= -16 (x² + (-4x) + (4) ) + 72
= -16 (x² - 4x + 4 ) + 72
= (-16)(x²) + (-16)(-4x) +(-16)(4) + 72
= -16x² + 64x - 64 + 72
= -16x² + 64x + 8 My guess is D ; 72 ???
I have no clue what the ; 72 means after the given answer. It must be a standard form thing I never learned.
