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kari74 [83]
4 years ago
7

I am lost on what to do

Mathematics
1 answer:
Neko [114]4 years ago
4 0
\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
\\\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
-----------------------------\\\\
\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\
-----------------------------\\\\
\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}

\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}
\\\\\\
\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0
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Allison is offered an annual salary of $24,500. What would be her biweekly gross pay? (Round to the nearest cent.) A. $2,041.67
bixtya [17]

Answer:

Option (B) is correct.

Allison biweekly gross pay is $942.31

Step-by-step explanation:

Given annual salary offered to Allison  = $24,500.

We have to calculate Allison biweekly pay that is pay Allison got for 2 weeks

To calculate biweekly we first find Allison weekly pay then multiply it by 2.

We know there are 52 weeks in a year.

So, weekly salary offered to Allison =\frac{24500}{52}=471.15(approx)

Biweekly salary will be = 2 × weekly salary

                                      = 2  × 471.15

                                       = 942.307(approx)

Thus, Allison biweekly gross pay is $942.31




6 0
3 years ago
Read 2 more answers
an equilateral triangle and a regular pentagon have the same perimeter. Each side of the pentagon is 3 inches shorter than each
klemol [59]
The answer is 4.5 for the side length of the pentagon and 7.5 is the side length for the triangle because 7.5*3(3 sides) = 22.5 and 4.5*5(5 sides)= 22.5. The perimeter is 22.5
6 0
3 years ago
Which statement is true about the patterns in the two tables ?
MAXImum [283]

Answer: The fourth one

Step-by-step explanation:

7 0
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Butyric acid ( c3h7cooh) is a weak acid . what is the ph of a 0.0250 m solution of this acid. ka = 1.5 x 10-5 (2 decimal places)
Wewaii [24]

The pH of the weak acid is 3.21

Butyric acid is known as a weak acid, we need the concentration of [H+] formula of weak acid which is given by this equation :

[H^{+}]=\sqrt{Ka . Ma}

where [H+] is the concentration of ion H+, Ka is the weak acid ionization constant, and Ma is the acid concentration.

Since we know the concentration of H+, the pH can be calculated by using

pH = -log[H+]

From question above, we know that :

Ma = 0.0250M

Ka = 1.5 x 10¯⁵

By using the equation, we can determine the concentration of [H+]

[H+] = √(Ka . Ma)

[H+] = √(1.5 x 10¯⁵ . 0.0250)

[H+] = 6.12 x 10¯⁴ M

Substituting the value of [H+] to get the pH

pH = -log[H+]

pH = -log(6.12 x 10¯⁴)

pH = 3.21

Hence, the pH of the weak acid c3h7cooh is 3.21

Find more on pH at: brainly.com/question/14466719

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8 0
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Between which two integers does square root of 129 lie?
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Between 11 and 12 (D)
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