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kari74 [83]
3 years ago
7

I am lost on what to do

Mathematics
1 answer:
Neko [114]3 years ago
4 0
\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
\\\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
-----------------------------\\\\
\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\
-----------------------------\\\\
\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}

\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}
\\\\\\
\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0
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For the five fair coins, the probability of coming up head when flipped is 0.5, so for two flips: 0.5*0.5 = 0.25, for each of these coins. So, the probability to take on of them is 5/8, and the probability of coming up with head: (5/8)*0.25 = 0.15625.

For the unfair coins, the probability of coming up with heads is 0.6, so for two flips: 0.6*0.6 = 0.36 for each unfair coins. The probability to chose one of them is 3/8, and the probability of coming up with head: (3/8)*0.36 = 0.135.

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P = 0.29125 x 100% = 29.125%

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