I am lost on what to do

Mathematics

1 answer:

Neko [114]4 years ago

4 0

$\bf sin({{ \alpha}})sin({{ \beta}})=\cfrac{1}{2}[cos({{ \alpha}}-{{ \beta}})\quad -\quad cos({{ \alpha}}+{{ \beta}})]
\\\\\\
cot(\theta)=\cfrac{cos(\theta)}{sin(\theta)}\\\\
-----------------------------\\\\
\lim\limits_{x\to 0}\ \cfrac{sin(11x)}{cot(5x)}\\\\
-----------------------------\\\\
\cfrac{sin(11x)}{\frac{cos(5x)}{sin(5x)}}\implies \cfrac{sin(11x)}{1}\cdot \cfrac{sin(5x)}{cos(5x)}\implies \cfrac{sin(11x)sin(5x)}{cos(5x)}$

$\bf \cfrac{\frac{cos(11x-5x)-cos(11x+5x)}{2}}{cos(5x)}\implies \cfrac{\frac{cos(6x)-cos(16x)}{2}}{cos(5x)}
\\\\\\
\cfrac{cos(6x)-cos(16x)}{2}\cdot \cfrac{1}{cos(5x)}\implies \cfrac{cos(6x)-cos(16x)}{2cos(5x)}
\\\\\\
\lim\limits_{x\to 0}\ \cfrac{cos(6x)-cos(16x)}{2cos(5x)}\implies \cfrac{1-1}{2\cdot 1}\implies \cfrac{0}{2}\implies 0$

You might be interested in

Plz answer right i need it for a quiz

lisov135 [29]

Answer:

Step-by-step explanation:

that is the answer

3 0

3 years ago

A number and it's absolute value are equal. If you subtract 2 from the number, the new number and it's absolute value are not eq

yaroslaw [1]

This means that the number is positive.

The absolute value is the distance away from 0 the number is.

So 1's absolute value would be 1, yet -5's absolute value would be 5.

So the number that's equal to its absolute value is positive, and the one that's not is negative.

So if you subtract 2 from the positive number, it must turn negative.

So 1 is a number that satisfies these conditions.

6 0

3 years ago

How does using a model help me multiply decimals by whole numbers?

valkas [14]

Counting them it simple

5 0

3 years ago

What is 6,4 rounded to the nearest whole number

Aleks04 [339]

6.4 rounded to the nearest whole number will be 6.

if the decimal was 5 or larger, it would’ve been 7.

6 0

3 years ago