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Serjik [45]
3 years ago
8

2/5y + 1/5x - 0.2y - 6 + -2 which are like terms. select all that apply​

Mathematics
1 answer:
horrorfan [7]3 years ago
3 0

\text{Like terms are } \frac{2}{5}y \text{ and } -0.2y

<em><u>Solution:</u></em>

<em><u>Given that the expression is:</u></em>

\frac{2}{5}y + \frac{1}{5}x -0.2y-6+(-2)

We have to select the like terms

"Like terms" means that terms that has same variables with same exponent and same ( or different ) coefficients

In the given expression, y is a variable

Two terms has y as variable : \frac{2}{5}y \text{ and } -0.2y

Here variable "y" is same in both terms and coefficients are different

"x" is also a variable in given expression. But there are no other terms with "x" as variable

So they form a like terms

\frac{2}{5}y + \frac{1}{5}x -0.2y-6+(-2)\\\\\frac{2}{5}y - 0.2y + \frac{1}{5}x -6 + (-2)

Thus the like terms are : \frac{2}{5}y \text{ and } -0.2y

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Y=-3/2x+2 <br>(i just need the y values for function table )<br><br>​
Liono4ka [1.6K]

Answer:

x     y

-2 = 5

0 = 2

2 = -1

4 = -4

4 0
3 years ago
A tortoise crawling at a rate of 0.1 mi/h passes a resting hare. The hare wants to rest another 30 min
pav-90 [236]

Answer:

The rabbit will run 264feet to get to the tortoise

Step-by-step explanation:

To solve this problem perfectly, we need to take note of the units and conversions involved.

The speed of the tortoise is 0.1 mi/hr

The speed of the hare is 5mi/hr

If the hare rests for another 30 minutes before he starts running the race, We are to get the distance covered by the tortoise under this 30 minutes.

The tortoise runs 0.1 miles in 1 hour

The tortoise will run x miles in 0.5 hours.

x = 0.5 X 0.1 =  0.05 miles.

Therefore, the distance covered by the Tortoise within 30 minutes is 0.05 miles.

The hare will have to run for 0.05 miles before he can catch up to the tortoise.

It is now unit conversion comes into play. We are converting the 0.05 miles to feet so we can get our final answer.

The answer in feet is 264 feet.

Therefore, the rabbit will run 264feet to get to the tortoise

3 0
2 years ago
What is 5/12 of 2/5 i need help
Marianna [84]

Answer:10/60

If need to  simply it is 1/6.

Step-by-step explanation: Mutiply 5/12 by 2/5 .

5 0
3 years ago
Find the inverse laplace<br><br> F(s)=11s/ s^2-12s+52
lions [1.4K]

Answer:

11e^{6t}\cos 4t+\frac{33}{2}e^{6t}\sin 4t

Step-by-step explanation:

We can write \frac{11s}{s^2-12s+52} as follows:

\frac{11s}{s^2-12s+52}\\=11\left [ \frac{s}{s^2-12s+52} \right ]\\=11\left [ \frac{s}{(s-6)^2+16} \right ]\\=11\left [ \frac{s-6+6}{(s-6)^2+16} \right ]\\=11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16}

To find:

L^{-1}\left [ \frac{11s}{s^2-12s+52 \right ]}\\=L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16} \right ]

We will use formulae:

L^{-1}\left \{ \frac{s-a}{(s-a)^2+b^2} \right \}=e^{at}\cos bt\\L^{-1}\left \{ \frac{b}{(s-a)^2+b^2} \right \}=e^{at}\sin bt

we get solution as :

L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+16} \right ]+\frac{66}{(s-6)^2+16} \right ]\\=L^{-1}\left [ 11\left [ \frac{s-6}{(s-6)^2+4^2} \right ]+\frac{66}{4}\left [ \frac{4}{(s-6)^2+4^2} \right ] \right ]\\=11e^{6t}\cos 4t+\frac{33}{2}e^{6t}\sin 4t

5 0
3 years ago
Find the x and y intercepts 8x-4y= -16
scZoUnD [109]

8x-4y=-16\\\\x-intercept\ for\ y=0:\\\\8x-4(0)=-16\\\\8x-0=-16\\\\8x=-16\qquad\text{divide both sides by 8}\\\\\boxed{x=-2\to(-2,\ 0)}\\\\y-intercept\ for\ x=0:\\\\8(0)-4y=-16\\\\0-4y=-16\\\\-4y=-16\qquad\text{divide both sides by (-4)}\\\\\boxed{y=4\to(0,\ 4)}

8 0
3 years ago
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