Answer:
A. 9 sqrt 2
Explanation:
Plug in hypotenuse and given side into
a^2 + b^2 = c^2 and solve.
Ok
y=-0.04x^2+8.3x+4.3
when the rocket reaches the ground (when height=0, ie when y=0), then the rocket will land, find the x coordinate
set y=0
0=-0.04x^2+8.3x+4.3
use quadratic formula
if you have ax^2+bx+c=0, then
x=

a=-0.04
b=8.3
c=4.3
x=

x=208.017 or -0.516785
xrepresents horizontal distance
you cannot have a negative horizontal distance unless you fired and theh wind blew it backwards
therefor x=280.017 is the answer
208.02 m
Answer:
] y=x-4
-2x+y=18
y - x = -4
y - 2x = 18
equation [2] for the variable y
[2] y = 2x + 18
// Plug this in for variable y in equation [1]
[1] (2x+18) - x = -4
[1] x = -22
// Solve equation [1] for the variable x
[1] x = - 22
// By now we know this much :
y = 2x+18
x = -22
// Use the x value to solve for y
y = 2(-22)+18 = -26
Step-by-step explanation:
please mark me as brainlist please
Answer:
(d) -11
Step-by-step explanation:
Each of the functions is evaluated in the usual way: put the number where the variable is in the expression and simplify.
h(-1) = -2(-1)² -3(-1) +1 = -2 +3 +1 = 2
f(2) = (2(2) +7)/(2 -3) = 11/-1 = -11
Then f(h(-1)) is ...
f(h(-1)) = f(2) = -11
Multiply
(x+a)(x+b) = x^2 + bx + ax + ab
looking at; x^2 + 10x + 24
can you see that
ab = 24
bx + ax = 10x
then
a + b = 10
use substitution: a = 10 - b
(10-b)b = 24
10b - b^2 = 24
-b^2 + 10b -24 = 0
now find the values for b using the quadratic equation. I'm on my phone so you'll have to plug the numbers in. let me know if you have any questions.