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Nezavi [6.7K]
3 years ago
11

4 a) Sebuah sekolah mengadakan lawatan sambil belajar ke Kuala Lumpur dengan membawa 44 orang penumpang termasuk seorang guru le

laki dan 3 orang guru perempuan. Diberi 2/5 daripada bakinya adalah murid lelaki. i. Berapakah bilangan murid perempuan yang menyertai lawatan itu?​
Mathematics
1 answer:
ratelena [41]3 years ago
5 0
Harap ini menolongmu :)

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7.325 divided by 1.465​
ki77a [65]
The correct answer for 7.325 divided by 1.465 is 5
7 0
4 years ago
Read 2 more answers
2x - x + 9 + 3x - 2 = 16
Mrac [35]

Answer:

x = 9/4 or 2.25

Step-by-step explanation:

First you will combine like terms. Combine 2x + 3x - x which gives you 4x. Then combine 9 - 2 and you get 7. Now the equation is 4x + 7 = 16. Subtract 7 from both sides to get x by itself. Now you have 4x = 9. To find what x equals, divide by 4 on each side. x = 9/4 or 2.25

3 0
3 years ago
What's the answer to this ?
WITCHER [35]

Answer:

3/41

Step-by-step explanation:

20+18+3=41 the proportional

So the arrow is in between x and 3

Which is x=3

Therefore x=3/41

7 0
3 years ago
Suppose there is a pile of quarters dimes and pennies with a total value of $1.07 how much of each coin can be present without b
Korolek [52]
Hello,

Very nice as problem.

2 solutions:
1 quater,8 dimes, 2 pennies
and
3 quaters,3 dimes, 2 pennies

since
107=( 0, 0, 107) but : 100= 0*25+ 0*10+ 100
107=( 0, 1, 97) but : 100= 0*25+ 1*10+ 90
107=( 0, 2, 87) but : 100= 0*25+ 2*10+ 80
107=( 0, 3, 77) but : 100= 0*25+ 3*10+ 70
107=( 0, 4, 67) but : 100= 0*25+ 4*10+ 60
107=( 0, 5, 57) but : 100= 0*25+ 5*10+ 50
107=( 0, 6, 47) but : 100= 0*25+ 6*10+ 40
107=( 0, 7, 37) but : 100= 0*25+ 7*10+ 30
107=( 0, 8, 27) but : 100= 0*25+ 8*10+ 20
107=( 0, 9, 17) but : 100= 0*25+ 9*10+ 10
107=( 0, 10, 7) but : 100= 0*25+ 10*10+ 0
107=( 1, 0, 82) but : 100= 1*25+ 0*10+ 75
107=( 1, 1, 72) but : 100= 1*25+ 1*10+ 65
107=( 1, 2, 62) but : 100= 1*25+ 2*10+ 55
107=( 1, 3, 52) but : 100= 1*25+ 3*10+ 45
107=( 1, 4, 42) but : 100= 1*25+ 4*10+ 35
107=( 1, 5, 32) but : 100= 1*25+ 5*10+ 25
107=( 1, 6, 22) but : 100= 1*25+ 6*10+ 15
107=( 1, 7, 12) but : 100= 1*25+ 7*10+ 5
107=( 1, 8, 2) is good
107=( 2, 0, 57) but : 100= 2*25+ 0*10+ 50
107=( 2, 1, 47) but : 100= 2*25+ 1*10+ 40
107=( 2, 2, 37) but : 100= 2*25+ 2*10+ 30
107=( 2, 3, 27) but : 100= 2*25+ 3*10+ 20
107=( 2, 4, 17) but : 100= 2*25+ 4*10+ 10
107=( 2, 5, 7) but : 100= 2*25+ 5*10+ 0
107=( 3, 0, 32) but : 100= 3*25+ 0*10+ 25
107=( 3, 1, 22) but : 100= 3*25+ 1*10+ 15
107=( 3, 2, 12) but : 100= 3*25+ 2*10+ 5
107=( 3, 3, 2) is good
107=( 4, 0, 7) but : 100= 4*25+ 0*10+ 0



4 0
3 years ago
Solve:<br><br> x^2 = 81<br><br> x^2 = -9 <br><br> x^2 = 20<br><br> 3x^2 = 125
sergeinik [125]
<span>x^2 = 81
x = </span>±√81
x = ±9<span>

x^2 = -9 no solutions 

x^2 = 20
x = </span>±√20
x = <span>±2</span>√5<span>

</span>3x^2 = 125 \\ &#10;x^2 =   \frac{125}{3} \\ x=б \sqrt{ \frac{125}{3} }<span>
</span>
3 0
3 years ago
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