B)comet nuclei are not uniform in composition
For the given question the answer to the first part is that frequency of sound will be 404.76 Hz. and answer to the second part will be that the initial frequency for which that place will have the highest level of sound intensity
Given, the speed of sound 340 m/s
a) L1 + L2 = 3.5 m
and Ld = | L1 - L2 | = ( 1.75 + 0.21 ) - (1.75 - 0.21 ) = 1.96 - 1.54 = 0.42 m
Ld = λ/2
λ = 2Ld = 2×0.42 = 0.84 m
and finally,
f = v/λ
f = 340/0.84
f = 404.76 hertz
Frequency came out to be 404.76 hertz in this case
b) For the first frequency
0.42 = λ
f = v/λ
f = 340 / 0.42
f = 809.52 Hertz
Frequency came out to be 809.52 Hertz in this case.
To conclude with we can say that the Frequency of the sound in case on came out to be 404.76 hertz which is approximately 405 Hz after applying all the concepts and calculations, in second case first frequency for which that location will be a maximum of sound intensity came out to be 809.52 Hertz after applying all the concepts and calculations.
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The only force acting on the ball, once it left the hand of the player, is the gravitational atraction of the earth. Once the ball reaches its maximum height, it starts a free fall movement under the action of earth's gravity.
Then the magnitude of the acceleration of the ball is the gravitational acceleration, g, approximatley 9.8 m/s^2
Answer:
Increase
Explanation:
The best way for me to visualize the relation between wavelength, frequency, and energy is to think about actual ocean waves. Wavelength is a measure of the distance between two equivalent points on consecutive waves (think wave peak to wave peak). Lets say you are building a sand castle and want to see how many waves hit your castle over a period of 10 seconds. If the distance between each wave is 10 ft and the wave is traveling at 1 foot per second then you will only have one wave hit your castle. If the wavelength is 1/2 that (5 ft) then you will have 2 waves hit your castle in the same amount of time. This is the same concept behind waves in physics. The smaller the distance between each wave, the more waves and therefore more energy that will be delivered.