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elena55 [62]
3 years ago
14

Suppose you had a point charge of 3.6 mC. show answer Incorrect Answer Calculate the magnitude of the electric field, in newtons

per coulomb, at a point 1.4 m away from this charge.
Physics
1 answer:
Ksivusya [100]3 years ago
5 0

Answer: 1.653 × 10⁴ N/C

Explanation: Given Q= 3.6× 10^-6

we assume there is a charge q placed at a distance r = 1.4m exerting an electric field strength towards Q.

Hence

F = kQq/r²

K= 9× 10^9

Now recall that E = F/q (electric field due to that charge)

E =( kQq/r²)/q

E = kQ/r² substituting the values gave the answer above.

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