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irina1246 [14]
3 years ago
14

How much wrapping paper would you need to cover a rectangular box that is 18.25 inches by 12 inches by 3 inches if you need 10%

more wrapping paper than the surface area of the box? Give your answer to the nearest square inch.
Mathematics
1 answer:
Reika [66]3 years ago
8 0

Answer:

  681 square inches

Step-by-step explanation:

The surface area of a rectangular prism of dimensions L, W, and H is given by ...

  A = 2(LW +H(L+W))

The surface area of the given box is ...

  A = 2(12·3 +18.25(12 +3)) = 2(36 +273.75) = 619.5 . . . square inches

The amount of wrapping paper required is 10% more than this value, so is ...

  paper required = (1 +.10)(619.5) = 681.45 ≈ 681 . . . square inches

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For more information on this visit

brainly.com/question/24131141?referrer=searchResults

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