How much wrapping paper would you need to cover a rectangular box that is 18.25 inches by 12 inches by 3 inches if you need 10%
more wrapping paper than the surface area of the box? Give your answer to the nearest square inch.
1 answer:
Answer:
681 square inches
Step-by-step explanation:
The surface area of a rectangular prism of dimensions L, W, and H is given by ...
A = 2(LW +H(L+W))
The surface area of the given box is ...
A = 2(12·3 +18.25(12 +3)) = 2(36 +273.75) = 619.5 . . . square inches
The amount of wrapping paper required is 10% more than this value, so is ...
paper required = (1 +.10)(619.5) = 681.45 ≈ 681 . . . square inches
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