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otez555 [7]
3 years ago
7

A driving school wants to find out which of its two instructors is more effective at preparing students to pass the state’s driv

er’s license exam. An incoming class of 100 students is randomly assigned to two groups, each of size 50. One group is taught by Instructor A; the other is taught by Instructor B. At the end of the course, 30 of Instructor A’s students and 22 of Instructor B’s students pass the state exam. Do these results give convincing evidence that Instructor A is more effective?A driving school wants to find out which of its two instructors is more effective at preparing students to pass the state’s driver’s license exam. An incoming class of 100 students is randomly assigned to two groups, each of size 50. One group is taught by Instructor A; the other is taught by Instructor B. At the end of the course, 30 of Instructor A’s students and 22 of Instructor B’s students pass the state exam. Do these results give convincing evidence that Instructor A is more effective?

Mathematics
1 answer:
jonny [76]3 years ago
7 0

Answer:

Yes, there is evidence to support that claim that instructor 1 is more effective than instructor 2

Step-by-step explanation:

We can conduct a hypothesis test for the difference of 2 proportions.  If there is no difference in instructor quality, then the difference in proportions will be zero.  That makes the null hypothesis

H0:  p1 - p2 = 0

The question is asking whether instructor 1 is more effective, so if he is, his proportion will be larger than instructor 2, so the difference would result in a positive number.  This makes the alternate hypothesis

Ha:  p1 - p2 > 0

This is a right tailed test (the > or < sign always point to the critical region like an arrowhead)

We will use a significance level of 95% to conduct our test.  This makes the critical values for our test statistic: z > 1.645.  

If our test statistic falls in this region, we will reject the null hypothesis.

<u>See the attached photo for the hypothesis test and conclusion</u>

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What number is equivalent to 80%, 0.8, 80/100
9966 [12]

Answer:

i think it is 80/100

Step-by-step explanation:

if it was 0.8 that would have been 8 so 80/100 is 80%

8 0
2 years ago
Suppose a triangle has two sides of length 32 and 35, and that the angle
pantera1 [17]

Answer:

The third side is around 58.043

Step-by-step explanation:

Use the law of cosines:  c^2=a^2+b^2-2abcos(C)

Plug in the two sides we know (into a and b) and the angle we know (into angle C).

Thus:

c^2=32^2+35^2-2(32)(35)cos(120)

Use a calculator:

c^2=3369\\

c=58.043087...

(Note: Make sure you're in Degrees mode.)

3 0
3 years ago
The coordinates of point A are (6, 2). The coordinates of point B are (2, 6). AB¯¯¯¯¯is transformed to form ​A′B′¯¯¯¯¯¯¯​, shown
postnew [5]

Answer:  

​AB¯¯¯¯¯​ is reflected across the y- axis to form A′B′¯¯¯¯¯¯¯​ .

8 0
3 years ago
The batteries from a certain manufacturer have a mean lifetime of 850 hours, with a standard deviation of 70 hours, assuming tha
matrenka [14]

To answer (a), we will need to find the Z value for 710 hours and 990 hours.

\begin{gathered} For\text{ 710} \\ Z\text{ = }\frac{x-\mu}{\sigma} \\ \text{    = }\frac{710-850}{70} \\ \text{    = -2} \\ p\text{ =0.0228 } \\ For\text{ 990:} \\ Z\text{ = }\frac{990-850}{70} \\ \text{ =2} \\ p\text{ = 0.9772} \end{gathered}\begin{gathered} To\text{ find P \lparen–2 \le Z \le 2\rparen} \\ =\text{ 0.9772 -0.0228} \\ =\text{ 0.9544} \\ =95.44\% \end{gathered}

B) 68% of data lies between one standard deviation of the mean.

850 +70 = 920

850 - 70 = 780

5 0
1 year ago
The ratio of the number of dogs the number of cats is 4:5. There are 270 animals on the rescue Farm. The number of dogs is 4/5.
mafiozo [28]

Answer:

<em>Here is the complete question:</em>

The ratio of the number of dogs to the number of cats is 4:5. There are 270 animals on the rescue farm. for each of the following statements, explain whether statements is true or false and why:

a. The number of dogs is 4/5 the number of cats.

b. 4/5 of the pets at the farm are dogs.

c. There are exactly 30 more cats than dogs.

d. There are exactly 30 dogs at the farm.

e. 5/9 of the pets at the farm are cats.

a,c and e are true statements.

Step-by-step explanation:

Let the number of dogs be "d' and number of cats be "c".

According to the question:

⇒ c+d=270   ...equation (i)

Arranging the ratio:

⇒ \frac{4}{5} = \frac{d}{c}

⇒ 4c=5d

⇒ c=(\frac{5}{4})d    ...equation (ii)

Plugging (ii) in equation (i).

⇒ c+d=270

⇒ \frac{5}{4} d+d=270

⇒ \frac{5d+4d}{4} =270

⇒ 9d=270\times 4

⇒ d=\frac{270\times 4}{9}

⇒ d=120

Number of dogs "d" = 120

Number of cats "c" = (270-120) = 150

Lets check each statement:

a.

The number of dogs is 4/5 the number of cats.

⇒ \frac{4}{5} \times 150

⇒ \frac{4\times 150}{5}

⇒ 120

Statement is true.

b.

4/5 of the pets at the farm are dogs.

⇒ \frac{4}{5} \times 270

⇒ 216

Number of dogs = 120

So the above statement is false.

c.

There are exactly 30 more cats than dogs.

⇒ c-d =30

⇒ 150-120=30

Statement is true.

d.

There are exactly 30 dogs at the farm.

False, as there are 120 dogs

e.

5/9 of the pets at the farm are cats.

⇒ \frac{5}{9} \times 270

⇒ 150

Statement is true.

So,

Statement  a,c and e are true as we could observe in the explanation.

8 0
3 years ago
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