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3 years ago

Please help me solve this. I really don’t get it

Mathematics

1 answer:

Yuki888 [10]3 years ago

8 0

The symbol is a representative of Pi. A endless number that equates to the diameter of a circle. It is asking what type of number group it belongs to

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I think it’s b but I’m not sure but can somebody help me

aev [14]

Answer:

Step-by-step explanation:

The small triangle is half the size of the entire triangle. 27/2 = 13.5

4 0

3 years ago

Answer this please :)

Elden [556K]

Answer:

Step-by-step explanation:

Distance formula: D = Square root (x^2-x^1)^2+(y^2-y^1)^2

H(-3,-4) Q(-8,1)

x1 y1. x2 y2

Plug in umbers

(-8+3)^2+(1+4)^2

(-5)^2 + (5)^2

25 + 25

Square root of 50 = 7.07106781187

7.1

Square root was always there I just don't know how to put it on a laptop.

Hope this helps!

8 0

3 years ago

Which table of values represents a linear function?

krek1111 [17]

Step-by-step explanation:

I'm learn this too hahaha

6 0

3 years ago

Read 2 more answers

Which two values of x are roots of the polynomial below?<br> 3x2-3x+1

QveST [7]

Answer:

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

Step-by-step explanation:

we have

$3x^2-3x+1$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2-3x+1=0$

$a=3\\b=-3\\c=1$

substitute in the formula

$x=\frac{-(-3)\pm\sqrt{-3^{2}-4(3)(1)}} {2(3)}$

$x=\frac{3\pm\sqrt{-3}} {6}$

Remember that

$i=\sqrt{-1}$

$x=\frac{1}{6} [3\pm i\sqrt{3}]$

The roots are

$x=\frac{1}{6} [3+ i\sqrt{3}]$

$x=\frac{1}{6} [3- i\sqrt{3}]$

6 0

3 years ago

An equation is shown below:

Drupady [299]

27x - 144 + 15 = 6x - 24
27x - 129 = 6x - 24
+129 +129
--------- --------
0 105
27x = 6x + 105
-6x -6x
----- ------
21x 0

21x = 105

21x/21 = 105/21

x = 5

Remove brackets
Gather like terms
Get rid of the lone number
Transfer
Divide

Hope this helps :)

4 0

3 years ago