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Bogdan [553]
4 years ago
5

A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate around the sun. To ac

count for the difference in time, every 4 years, a leap year takes place. A leap year is when a year has 366 days: An extra day, February 29th. The requirements for a given year to be a leap year are: 1) The year must be divisible by 4 2) If the year is a century year (1700, 1800, etc.), the year must be evenly divisible by 400 Some example leap years are 1600, 1712, and 2016. Write a program that takes in a year and determines whether that year is a leap year.
Computers and Technology
2 answers:
katrin [286]4 years ago
6 0

Answer:

i_year=int(input(""))

#check leap year

if((i_year % 4 == 0 and i_year % 100 != 0) or (i_year % 400 == 0)):

  print("{} is a leap year.".format(i_year))

else:

  print("{} is not a leap year.".format(i_year))

Explanation:

GREYUIT [131]4 years ago
4 0

Answer:

import java.util.Scanner;

public class LabProgram {

  public static void main(String[] args) {

      Scanner scnr = new Scanner(System.in);

      int inputYear;

      boolean isLeapYear;

      isLeapYear = false;

      inputYear = scnr.nextInt();

      // If a year is divisible by 400,  then it is a leap year

      if (inputYear % 400 == 0)

          isLeapYear = true;

      // If a year is divisible by 100,  then it is not a leap year

      if (inputYear % 100 == 0)

          isLeapYear = false;

      // If a year is divisible by 4,  then it is a leap year

      if (inputYear % 4 == 0)

          isLeapYear = true;

      if(isLeapYear)

          System.out.println(inputYear + " is a leap year.");

      else

          System.out.println(inputYear + " is not a leap year.");

  }

}

Explanation:

  • Take the year as an input from user and store it to inputYear variable.
  • If the year is a century year, check if the year is divisible by 400 ( the year must be evenly divisible by 400 ),  then set the boolean isLeapYear to true. If a year is divisible by 100,  then set the boolean isLeapYear to false. If a year is divisible by 4,  then set the boolean isLeapYear to true.
  • Check if isLeapYear is true, then print that it is a leap year. Otherwise, print that it is not a leap year.

Output:

1712

1712 is a leap year.

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Explanation:

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Complete question :

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Answer:

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Explanation:

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Answer:

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tmp = words[1]

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words[0] = tmp

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Date Time Manipulation Exploration If you start from Jan 1st, 1757, and repeatedly add 8 days, until you hit 1800, how many time
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Answer:

from datetime import datetime, date, timedelta

def count_weekdays(start_date, add_days, stop_year, weekday):

   my_date = start_date

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try:

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