1 imperial foot has approximately 30.48 metric centimeters, and for one present we need 3 ft, or namely 3(30.48) cm, how many can we get from 102 cm? 102 ÷ 3(30.48) ≈ 1.1155, so barely just one present.
Answer:
x = -3
Step-by-step explanation:
Okay, the first thing to do is get that 8 away from the fraction. How can we do it? When you have 2³ you have 8, is the same thing, so let's do it:
2³⁰/(2³)⁹ = 2^x
When you have a number with the shape (a^x)^y, you can write it as a^(x•y), so:
(2³)⁹ = 2^3•9 = 2²⁷
Now we have:
2³⁰/2²⁷ = 2^x
When you have a division like this: (a^x)/(a^y), you can write it as a^(x-y), so:
2^(30-27) = 2^x
2^-3 = 2^x
Now you know that x = -3
1) x+y = 170
x-y = 26
2) Subtract the two equations from each other. Doing this you get 2y = 56.
So the value of y is 28. Then plug in the value of y into any of the two equations and solve for x.
x-28 = 26
x = 54
3) When writing solutions as an ordered pair, the x value always comes first followed by the y value. So it would be (54, 28).
<h2> (1 ,2) (2,-3)</h2><h2>(x1,y1) (x2, y2)</h2>
<h2> Distance formual</h2>
<h2> √(x2-x1)^+(y2-y1)^</h2>
<h2>= √(2-1)^+(-3-2)^</h2><h2>= √(1)^+(-5)^ [here square root and </h2><h2> square get cancelled]</h2><h2>= (1)+(-5)</h2><h2>= 1-5</h2><h2>= - 4</h2>
The two at the top technically means how many times the number in the bracket times ITSELF by, so its technically -3 x -3 which is +9 , cause a negative x negative = positive
