6 multiplied by negative 7 would be negative 42. Negative 42 added by negative 8 would be negative 34.
Answer:
There are a few solutions because there are some fractions and decimals between 8 and 10
Step-by-step explanation:
Let the unknown number be 'x'
If the number is greater than 8 and the same number is less than 10, this can be expressed as;
x>8 and x < 10
Note that if x>8, then 8<x
The resulting inequalities are now;
8<x and x<10
Combining both inequalities we have: 8<x<10
Since the inequality didn't tell us that the variable 'x' is equal to 8 and 10, this means that our solution falls between 8 and 10 and the value of integer that falls within this range is 9. Other values that falls within this range are decimals and fractions.
Therefore it can be concluded that there are a few solutions because there are some fractions and decimals between 8 and 10
Let
x-----------> <span>uniform width surrounding the picture
we know that
(10+2x)*(12+2x)=224-----> 120+20x+24x+4x</span>²=224
4x²+44x+120-224=0
4x²+44x-104=0
using a graph tool-----> to resolve the second order equation
see the attached figure
the solution is
x=2 in
the answer is2 inches


No, since 0 doesn't belong to the domain.
The perimeter = 4 * length of a semicircle of radius 5 == 4* pi * 5 = 20 pi cm
The area of one of the clear parts = 1/2 area of square - area semicircle
= 1/2 * 10^2 - 1/2 pi *5^2 = 50 - 12.5pi
So area of shaded parts = area of square - 4 (50 - 12.5pi)
= 100 - 200 + 100pi = (100pi - 100) cm^2