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saveliy_v [14]
4 years ago
8

If 270 wats of power is used in 42 seconds how much work is done ?

Physics
1 answer:
pentagon [3]4 years ago
6 0

Answer:

power is given by work done divide time taken

P=w/t

therefore Pt=w

270x42=11,340.J

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Which of the following statements is not true of vibrations?
defon

Answer:

b

Explanation:

5 0
3 years ago
how long will it take the bird to cover a ground distance of 550 km from north to south? (note that even on cloudy nights, many
Trava [24]

The direction of the bird's velocity can be adjusted so that the wind and the resulting bird velocity will both be in the southerly direction.

(a) The bird should fly at an angle of roughly South 23.58° East if it wants to move directly southward in relation to the earth.

(b) The bird would need around 5.46 hours to fly 500 kilometers from North to South.

The components of the velocity are v(x) and v(y).

The magnitude of the velocity of the bird is 100 km/h

The orientation of the bird corresponds to that of North and South.

The magnitude of the velocity of the wind is 40 km/h

East-west is the direction of the wind.

(a) The component vector of the two velocities are;

The velocity of the bird, v(y) = -100(j)

The velocity of wind, v(x) = 40(i)

If the bird has a component of velocity to accommodate the wind velocity, the direction of its movement will be southerly.

Let θ be the angle of the direction of the bird relative to the negative x-axis, therefore:

-100(j) × cos(θ) = -40·i

θ = cos⁻¹(40/100)

θ ≈ 66.42° in the third quadrat, given that both the y, and x, values are negative.

In the South-West direction, the angle is:

90 - 66.42 ≈ 23.58°

Therefore, to fly directly southward relative to the ground, the bird should fly in the direction of south 23.58° east.

(b) The following is given as the component of the bird's southerly velocity when traveling in the new direction:

v(s) = 100 × sin(θ)

Hence,

Southward velocity,  v(s) = 100 × sin(66.42°)

The time t it takes to travel 500 km, is given as:

d = v(s)t

500 = 100 × sin(66.42°)(t)

t = 5.46 hrs

The bird would need 5.46 hours to fly 500 kilometers from North to South.

Learn more about velocity here:

brainly.com/question/80295?source=archive

#SPJ4

The complete question is mentioned below:

Canada geese migrate essentially along a north–south direction for well over a thousand kilometers in some cases, traveling at speeds up to about 100 km/h. If one goose is flying at 100 km/h relative to the air but a 40-km/h wind is blowing from west to east,

(a) at what angle relative to the north–south direction should this bird head to travel directly southward relative to the ground?

(b) How long will it take the goose to cover a ground distance of 500 km from north to south? (Even on cloudy nights, many birds can navigate by using the earth’s magnetic field to fix the north–south direction.)

5 0
2 years ago
Weegy which of the following statments is an accurate description of viberation?
zmey [24]

There is no accurate description on the list you provided.

6 0
4 years ago
Read 2 more answers
Some gas is trapped in a large syringe by a piston.The atmospheric pressure is 100kpa.The pressure gauge indicates that the gas
jasenka [17]

Answer: The new gas pressure is 150 kPa.

Explanation :

Boyle's Law: This law states that pressure is inversely proportional to the volume of the gas at constant temperature and number of moles.

P\propto \frac{1}{V}     (At constant temperature and number of moles)

P_1V_1=P_2V_2  

where,

P_1 = initial pressure of gas  = (100+200) kPa = 300 kPa

P_2 = final pressure of gas  = ?

V_1 = initial volume of gas  = v

V_2 = final volume of gas  = 2v

300\times v=P_2\times 2v  

P_2=150kPa

Therefore, the new gas pressure is 150 kPa.

8 0
3 years ago
g A ball is thrown against the wall and bounces back with the same velocity. What type of collision is this
Softa [21]

Answer:

Perfectly elastic collision

Explanation:

In a closed system, an elastic collision is a type of collision between two bodies, where the total momentum and kinetic energy are conserved.

We are told from the problem that the ball bounces back with its original velocity. For the ball to bounce back to the thrower in the first place, this is our first hint that the collision is elastic. If the collision was inelastic, the ball would most likely have stuck to the wall.

In addition to that, the velocity of the ball remains fairly unchanged even after the collision. This confirms that the kinetic energy it had before the collision is the same as the kinetic energy it has after the collision.  

As a result of this, the collision is perfectly elastic

8 0
3 years ago
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