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ludmilkaskok [199]
3 years ago
9

Help please..................

Physics
1 answer:
Shtirlitz [24]3 years ago
7 0
<h3><em>If two objects with the same charge are brought towards each other the force produced will be repulsive, it will push them apart. If two objects with opposite charges are brought towards each other the force will be attractive, it will pull them towards each other.</em></h3><h3><em>hope it helps.... thank you....</em></h3>
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What type of lens is used to correct nearsightedness.
Stella [2.4K]

Answer:

Concave lenses are used in eyeglasses that correct myopia or nearsightedness.

5 0
2 years ago
Calculate the wavelength (in nm) of light that produces its first minimum at an angle of 21.0° when falling on a single slit of
Cerrena [4.2K]

To solve this problem it is necessary to apply the related concepts to the principle of overlap, specifically to single slit diffraction experiment concept.

Mathematically this can be expressed as:

dsin\theta = m\lambda

Where,

d = Width of the slit

\lambda =Wavelength

\theta = Angle relative to the original direction of the light

m = Any integer which represent the order of the equation (number of repetition of the spectrum)

To solve the problem we need to rearrange the equation and find the wavelength

\lambda = \frac{dsin\theta}{m}

Our values are given as,

d = 1.46\mu m = 1.46*10^{-6}m

\theta = 21\°

m = 1

Replacing in our equation we have,

\lambda = \frac{dsin\theta}{m}

\lambda = \frac{(1.46*10^{-6})sin(21)}{1}

\lambda = 5.232*10^{-7}m

\lambda = 523.2nm

Therefore the wavelength is 523.2nm

7 0
4 years ago
The latitude of the city of Arlington is about 32.7357°. Calculate the following: (a) The angular speed of the Earth. (b) The li
julia-pushkina [17]

Answer:

Explanation:

a ) The earth rotates by 2π radian in 24 x 60 x 60 s

so angular speed ( w )  = 2π / (24 x 60 x 60)  = 7.268 x  10⁻⁵ rad / s

b ) Linear speed of city of Arlington ( v )  = w r = w R Cosλ where R is radius of the earth and λ is latitude .

v = 7.268 x 10⁻⁵ x  6.371 x 10⁶ cos 32.7357

389.5 m /s

acceleration = w² r = w² R Cos 32.7357

= (7.268 x 10⁻⁵ )² x 6.371 x 10⁶ x cos 32.7357

=283.08 x 10⁻⁴ m/s²

c) velocity ratio =

w r /w R =

R cos 32.73/ R  

= Cos 32.73

= 0.84 .

6 0
4 years ago
A bicyclist is coasting straight down a hill at a constant speed. The mass of the rider and bicycle is 96.0 kg, and the hill is
mr_godi [17]

Answer:

 The force applied 275 N in a direction parallel to the hill

Explanation:

Newton's second law is adequate to work this problem, in the annex we can see a free body diagram, where the weight (W) is vertical, the friction force (fr) is parallel to the surface and the normal (N ) is perpendicular to it. In general for these problems a reference system is taken that is parallel to the surface and the Y axis is perpendicular to it.

Let us decompose the weight into its two components, the angle T is taken from the axis and

            Wx = W sin θ

            Wy = W cos T

We write Newton's second law

              ∑ F = m a

X axis

          The cyclist falls at a constant speed, which implies that the acceleration is zero

              fr - W sin θ = 0

              fr = mg sin θ

              fr = 96 9.8 without 17

              fr = 275 N

When the cyclist returns to climb the hill, he must apply the same force he has to overcome the friction force that always opposes the movement .  The force applied 275 N in a direction parallel to the hill

5 0
3 years ago
Max is a network technician who just terminated the ends on a new copper cable used between two legacy switches. When he connect
Olegator [25]

Answer:

The cable used is a straight through cable.

Explanation:

The cable used here is a straight through cable, that is why it fails to establish the connection.

Cross-over cables are used to communicate over legacy switch. It is used to connect computing devices directly.

In a cross over cable, signal gets transmit from one end of the device to the other.

7 0
3 years ago
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