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3 years ago

Consider the functions:

Mathematics

2 answers:

diamong [38]3 years ago

8 0

The x and y that’s the answer

jolli1 [7]3 years ago

5 0

The x and y axis so that’s why it’s true

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If 6 tomatoes are for $4, how much does 15 tomatoes cost?

Mariana [72]

$22.50 is the cost of 15 tomatoes

3 0

4 years ago

Write this polynomial expression in its simplest form. Show your work.

Zanzabum

Step-by-step explanation:

(3x² + 4x - 8) - (-2x² + 4x + 2)

[3 - (-2) = 5] , [ 4 - 4 = 0] , [ (-8) - 2 = -10]

5x² + 0x - 10

(or)

5x² - 10

6 0

4 years ago

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Name the polygon. Write whether it is regular or not regular.

andrew-mc [135]

Answer:

since the polygon has eight sides, it's an octagon and no, it's not regular since length of all sides of a regular polygon must be equal but in that octagon, not all sides are equal.

8 0

3 years ago

Suppose that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage

Zigmanuir [339]

Answer:

We conclude that the percentage of blue candies is equal to 29%.

Step-by-step explanation:

We are given that in a random selection of 100 colored candies, 28% of them are blue. The candy company claims that the percentage of blue candies is equal to 29%.

Let p = population percentage of blue candies

So, Null Hypothesis, $H_0$ : p = 29% {means that the percentage of blue candies is equal to 29%}

Alternate Hypothesis, $H_A$ : p $\neq$ 29% {means that the percentage of blue candies is different from 29%}

The test statistics that will be used here is One-sample z-test for proportions;

T.S. = $\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n} } }$ ~ N(0,1)

where, $\hat p$ = sample proportion of blue coloured candies = 28%

n = sample of colored candies = 100

So, the test statistics = $\frac{0.28-0.29}{\sqrt{\frac{0.29(1-0.29)}{100} } }$

= -0.22

The value of the z-test statistics is -0.22.

Also, the P-value of the test statistics is given by;

P-value = P(Z < -0.22) = 1 - P(Z $\leq$ 0.22)

= 1 - 0.5871 = 0.4129

Now, at a 0.10 level of significance, the z table gives a critical value of -1.645 and 1.645 for the two-tailed test.

Since the value of our test statistics lies within the range of critical values of z, so we insufficient evidence to reject our null hypothesis as it will not fall in the rejection region.

Therefore, we conclude that the percentage of blue candies is equal to 29%.

4 0

3 years ago

Find the 16th term for the sequence a(n)=7-2n.

N76 [4]

In the expression that you are given, n is the is number in the sequence. So in this scenario, n=16. So substitute the 16 into the equation. $a(n)=7-2(16)=7-32=-25$ . So the 16th term in the sequence is -25.

3 0

3 years ago

Read 2 more answers