Mr. Pham mowed 2/7 of his lawn. his son mowed 1/4 of the lawn who mowed the most? How much of the lawn still needs to be mowed

Mathematics

2 answers:

liubo4ka [24]2 years ago

8 0

The answer is 2/7, so Mr. Pham

lutik1710 [3]2 years ago

5 0

Answer:

I believe the answer is 13/18

Step-by-step explanation:

if is not sorry but this is for 5th grade exit ticket only

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Help please i don’t know how to do it

nekit [7.7K]

Answer:

x + 3y = 15

Step-by-step explanation:

Line is passing through the points $(3, \:4) = (x_1,\:y_1)\:and\: (9, 2)=(x_2,\:y_2)$

Slope of line (m)= (2 - 4)/(9 - 3) = -2/6 = -1/3

Equation of line in point-slope form is given as:

$y-y_1 =m(x-x_1)$

Plugging the values of $x_1,\: y_1\: and \: m$ in the above equation we find:

$y-4 =-\frac{1}{3}(x-3)$

$\implies 3y-12 =-x+3$

$\implies x+ 3y =12+3$

$\implies \huge {\orange{\boxed{x+ 3y = 15}}}$

This is the required equation of line in the form $\red{\bold{ax + by = c}}$

5 0

2 years ago

In a free-fall experiment, an object is dropped from a height of h = 400 feet. A camera on the ground 500 ft from the point of i

PilotLPTM [1.2K]

Hmmm the object, is at rest, when dropped, so it has a velocity of 0 ft/s

the only force acting on the object, is gravity, using feet will then be -32ft/s²,

was wondering myself on -32 or 32.. but anyhow... we'll settle for the negative value, since it seems to be just a bit of convention issues

so, we'll do the integral to get v(t) then

$\bf \displaystyle \int -32\cdot dt\implies -32t+C
\\\\\\
\textit{object moves from \underline{rest}, so velocity is 0 at 0secs}
\\\\\\
-32(0)+C=0\implies C=0\implies \boxed{v(t)=-32t}
\\\\\\
\textit{now to get the positional s(t)}
\\\\\\
\displaystyle \int -32t\cdot dt\implies -16t^2+C
\\\\\\
\textit{the initial \underline{position} was 400ft away at 0secs}
\\\\\\
-16(0)^2+C=400\implies C=400\implies \boxed{s(t)=-16t^2+400}$

when will it reach the ground level? let's set s(t) = 0

$\bf s(t)=-16t^2+400\implies 0=-16t^2+400\implies \cfrac{-400}{-16}=t^2
\\\\\\
25=t^2\implies \boxed{5=t}$

part B) check the picture below