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denis23 [38]
3 years ago
5

What is the distance between the points (-2, 5) and (4, -3)?

Mathematics
1 answer:
Soloha48 [4]3 years ago
8 0
See the attachment..........

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If we wanted to know how high a 5th-grade student could jump, how many students would be reasonable to test? 5, 12, 30, or 200.
77julia77 [94]
The right amount to test would be 30.

200 is to many kids and 12 is not enough.

Hope this Helps!!
4 0
3 years ago
Locate the point on the line segment between A(3, -5) and B(13, -15) given that the point is 4/5 of the way from A to B. Show yo
SVETLANKA909090 [29]

Answer:

C ( 11 , -11 )

Step-by-step explanation:

Solution:-

We are given two points in the cartesian coordinate system as:

                   A ( 3 , -5 )              B ( 13 , -15 )

The point C lies on the line segment from A to B. The ratio of segment given is:

                              AC / AB = 4 / 5

To solve such type of problems. We will use vector equation of line AC.

To form a vector equation of line representing AB. We will first determine the direction vector ( d ) that is parallel to the line AB as follows:

                 d = OB - OA

                 d = < 13 , -15 > - < 3 , -5 >  

                 d = < 10 , -10 >

The fixed point on the line is taken. We will take point A. The vector equation of line from point A to point B is expressed as:

                < x , y > = OA + s*d

                < x , y > = < 3, -5 > + s* < 10 , -10 >  

The above equation satisfies all the points that lies on the line AB. To determine the coordinates of ( C ). We will plug in the appropriate value of parameter ( s ) and evaluate.

So point C is 4/5 th the magnitude of the distance AB from A. Hence, s = 4/5 as follows:

               < x , y > = < 3 , -5 > + ( 4/5 ) * < 10 , -10 >  

               < x , y > = < 3 , -5 > + < 8 , -8 >  

              < x , y > = < 11 , -11 >   ... Answer

8 0
3 years ago
A line contains the points R (-1, 8) S (1, 4) and T (6, y). Solve for y. Be sure to show and explain all work.
Nikitich [7]

Given:

A line contains the points R(-1, 8), S(1, 4) and T(6, y).

To find:

The value of y.

Solution:

Three points are collinear if:

x_1(y_2-y_3)+x_2(y_3-y_2)+x_3(y_1-y_2)=0

A line contains the points R(-1, 8), S(1, 4) and T(6, y). It means, these points are collinear.

-1(4-y)+1(y-8)+6(8-4)=0

-4+y+y-8+48-24=0

2y+12=0

Subtract 12 from both sides.

2y=-12

Divide both sides by 2.

y=\dfrac{-12}{2}

y=-6

Therefore, the value of y is -6.

3 0
3 years ago
What is 2/6 simplified?
m_a_m_a [10]
1/3 is the answer. Hope this helps
3 0
3 years ago
Help me please and sorry about the points it doesn’t let me do more than that
kkurt [141]
I think the slope would be 1.5
explanation: i’m not sure but rise/run,
y2-y1/x2-x1
(1,1.5) (4,6)
6-1.5/4-1=4.5/3=1.5
8 0
3 years ago
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