his score was increased... so if he is now at 67 and it was increased by 7 so his first grade would have been 60.
Hi,
To solve this problem, Let us take the LCM of 10 and 16 which will come 80.
Now suppose the cost price of 10 tables =₹n CP of 80 tables will be ₹ 8n
According to the question, CP of 10 tables is equal to the SP of 16 tables, then
the SP of 16 tables will also be ₹ n.
So, SP of 80 tables will be ₹ 5n
So, Loss = CP-SP
→ 8n - 5n = ₹ 3n
Loss%= (3n×100)/8n
Loss%= 37.5%.
Hence the correct answer will be a <u>loss of 37.5%.</u>
Vanessa: a dime = 10 cents = 0.10
A penny = 1 cent = 0.01
6 x 0.10 = 0.60
2 x 0.01 = 0.02
Total = 0.60 + 0.02 = 0.62
Joachim : a dollar = 1.00
3 x 0.10 = 0.30
5 x 0.01 = 0.05
Total = 1.00 + 0.30 + 0.05 = 1.35
Jimmy: total = 5.00 + 0.07 = 5.07
Total of all 3: 0.62 + 1.35 + 5.07 = $7.04
This is less than $8 so they don’t have enough.
They need: 8.00 - 7.04 = $0.96 more
A because the feed sets discounts rate and primes
