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soldi70 [24.7K]
3 years ago
9

PLEASE Help Me SOLVE NUMBER 3 PLEASE

Mathematics
1 answer:
LuckyWell [14K]3 years ago
7 0
I believe the answer to your question is C
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goldenfox [79]

Answer:

#19 is C

# 20 is True, False, and False

Step-by-step explanation:

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Identify the following sequences as linear, exponential, or other. For the linear and exponential, identify the rate of change a
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2 years ago
Consider a normal distribution with mean 23 and standard deviation 7. What is the probability a value selected at random from th
Trava [24]

Answer:

0.5 = 50% probability a value selected at random from this distribution is greater than 23

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 23, \sigma = 7

What is the probability a value selected at random from this distribution is greater than 23?

This is 1 subtracted by the pvalue of Z when X = 23. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{23 - 23}{7}

Z = 0

Z = 0 has a pvalue of 0.5

0.5 = 50% probability a value selected at random from this distribution is greater than 23

5 0
3 years ago
Read 2 more answers
19
Nikolay [14]

Answer: 1 year

Step-by-step explanation:

510,000 × .08 = 40,800

40,800 is way more then 5k so yeah 1 year

But realistically less than that.

7 0
3 years ago
The first day of the food drive missed easily for cans of beans 7 boxes of noodles and for cans of soup. Find the ratio of cans
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There is only the number 7 in this question I can’t really help with one number
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3 years ago
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