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dem82 [27]
3 years ago
12

Please helppp!!!!!!!!!

Mathematics
2 answers:
Jet001 [13]3 years ago
7 0

The point is 1,15 letter a.  Here is the table : -2,0.12 -1,0.6 0,3 1,15

koban [17]3 years ago
3 0

It is (1,15). I recommend using a website called desmos because it helps with graphing.

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Given: JK tangent, KH=16, HE=12 Find: JK.
Y_Kistochka [10]

Answer: JK=8

Step-by-step explanation:

You can observe in the figure that JK is a tangent and KH is a secant and both intersect at the point K. Then, according to the Intersecting secant-tangent Theorem:

JK^2=KE*KH

You know that:

KH=KE+HE

Then KE is:

KE=KH-HE

KE=16-12

KE=4

Now you can substitute the value of KE and the value of KH into  JK^2=KE*KH and solve for JK. Then the result is:

JK^2=4*16\\JK^2=64\\JK=\sqrt{64}\\JK=8

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3 years ago
How do you write 64% as A fraction
slavikrds [6]

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Step-by-step explanation:

64% =

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3 years ago
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Carl makes baskets with bags of coffee or boxes of tea. He has 72 bags of coffee and 56 boxes of tea. He wants to put an equal n
masha68 [24]

Answer:

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4 0
3 years ago
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Find all polar coordinates of point p where p= (5, pi/3)
m_a_m_a [10]

The polar coordinate of any point can be written as:

(r, θ) = (r, θ + 2nπ)                                           when positive

 (r, θ) = [ - r, θ + (2n + 1)π ]                            when negative

The polar coordinates of this given point P is: P = (r, θ) = (5, π/3).

When the value of r is positive, the polar coordinate is written as P= (5, π/3) = (5, π/3 + 2nπ)

When the value of r is negative, the polar coordinate is written as P = (5, π/3) = [ - 5, π/3 + (2n + 1)π] where n is any integer.

Therefore all polar coordinates of point P are (5, π/3 + 2nπ) and [ - 5, π/3 + (2n + 1)π ].

5 0
3 years ago
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