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Ber [7]
3 years ago
14

What is the entire object shown in the image?

Biology
2 answers:
NARA [144]3 years ago
3 0

Answer:eukaryote

Explanation:

galben [10]3 years ago
3 0

Answer:

B) Eukaryote

Explanation:

Edge 2020

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Bir canlının solunum sisteminin aşağıdaki özellik-
Aliun [14]

Answer:

cevap b imiş kunduzdan baktım

6 0
3 years ago
What creates our climate?
Angelina_Jolie [31]
The climate is changing very quickly and comparison in todays time back then it was changing very slowly thats what i know about that 

hope it helps you out good luck

8 0
3 years ago
Please help me out with these practice questions.<br> Thank you!
Oduvanchick [21]

Answer:

1. B.

2. B.

3. A.

Explanation:

1. So, the mother does not but the father does carry the gene for polydactyly. Which means that, the offspring was born Pp and, the dominant trait (P) was exposed.

2. A heterozygous trait is one that has both allele forms (in this case, d and D. If both of the parents are Dd, the offspring will also be Dd, and therefore, he has 1/2 chance of being born deaf.

3. Both you and your spouse will be heterozygous (Ee), therefore, since unattached earlobes are dominant

3.1 When two heterozygous traits are bred, you will get the following combinations: yy, Yy, Yy and YY. Which means that your offspring had a 1/4 chance of having attached earlobes, and that is what happened.

3.2 The third option is incorrect, because when you breed 2 homozygous recessive (ee) traits, all of your offspring will be homozygous recessive (ee), which means that the parents would have to be homozygous recessive, but, they cannot since the dominant trait has applied to them.

4 0
4 years ago
The spikes on pollen grains probably
Viefleur [7K]

Answer:

<h3>a) allow pollen grain to stick to insect</h3>
6 0
3 years ago
The bones from an animal found at an archaeological dig have a C614 activity of 0.10 Bq per gram of carbon. The half-life of C61
erastova [34]

C14 is an isotope used in radiocarbon dating techniques to date organic matter remains. The age of these bones is approximately<u> 6890 years.</u>

<h3>What is Carbon 14?</h3>

Carbon 14, also known as radiocarbon, is a radioactive carbon isotope.

Isotopes are the atoms of the same element -carbon- that vary in neutrons and, hence, in their massic number. They are alternative forms of the same element.

The radioactive C14 nucleus contains 6 protons and 8 neutrons and has a half-life of 5730 years.

The term half-life is a reference. It means that an organism that has been dead for 5730 years has half the C14 amount or concentration than the same organism had when it was alive.

Knowing the half-life of an element is useful to determine the age of the dead matter.

C14 is used in radiocarbon dating techniques or methods to estimate the age of fossils. This is a reliable technique used for dating organic samples that are less than 50,000 years old.

<u>Available data</u>:

  • The half-life of C14 is 5730 years
  • Bones activity of 0.10 Bq per gram of carbon

To answer this question we can make use of the following equation

Ln (C14T₁/C14 T₀) = - λ T₁

Where,

  • C14 T₀ ⇒ Amount of carbon in a living body. We know, by bibliography, that living organism activity is 0.23 Bq per gram of carbon. So, C14 T₀ = 0.23 Bq/g
  • C14T₁ ⇒ Amount of carbon in the dead body. C14T₁ = 0.1 Bq/g
  • λ ⇒ radioactive decay constant = (Ln2)/T₀,₅
  • T₀,₅ ⇒ The half-life of carbon 14 = 5730 years
  • T₀ = Time when the organism was alive
  • T₁ = Age of bones

Let us first calculate the radioactive decay constant.

λ = (Ln2)/T₀,₅

λ = 0.693/5730

<u>λ = 0.0001209</u>

Now, let us calculate the first term in the equation

Ln (C14T₁/C14 T₀) = Ln (0.1/0.23) = Ln 0.4347 =<u> - 0.833</u>

Finally, let us replace the terms, clear the equation, and calculate the value of T₁.

Ln (C14T₁/C14 T₀) = - λ T₁

- 0.833 = - 0.0001209 x T₁

T₁ = - 0.833 / - 0.0001209

T₁ =  6889.99 ≅ <u>6890 years</u>

The bones are approximately<u> 6890 years.</u>

You can learn more about dating organic matter with carbon14 at

brainly.com/question/4149380

#SPJ1

6 0
3 years ago
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