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3 years ago

12

I need help in the two questions

1 answer:

Sholpan [36]3 years ago

3 0

Y-5=3-9 (y+2)
Solve for y
Distribute the 9 to (y+2)
Y-5=3-9y-18
Y-5=-15-9y
+9y to both sides
10y-5=-15
+5 to both sides
10y=-10
÷10 both sides
Y= -1

2 (x-7)-10=12-4x
Solve for X
Distribute 2 to (x-7)
2x-14-10=12-4x
2x-24=12-4x
+4x to both sides
6x-24=12
+24 to both sides
6x=36
÷6 to both sides
X=6

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Convert 15/125 As A Decimal Using Long Division<br><img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B15%7D%7B125%7D%20" id="TexForm

denpristay [2]

0 . 1 2

125 ) 15.00

125

------

250

250

-----

The answer is 0.12

7 0

3 years ago

10÷250 and please no links

Juli2301 [7.4K]

Answer:

10÷250

= 0.04

Step-by-step explanation:

that's the answers

4 0

3 years ago

Read 2 more answers

Use the triangle below to find cos V.

Semenov [28]

Answer:

$cos\ V = \frac{2\sqrt{29}}{29}$

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

$cos\theta = \frac{Adjacent}{Hypotenuse}$

In this case:

$cos V= \frac{TV}{UV}$

Where

$TV = 6$

and

$UV^2 = TV^2 + TU^2$ -- Pythagoras

$UV^2 = 6^2 + 15^2$

$UV^2 = 261$

Take square roots

$UV = \sqrt{261$

$UV = \sqrt{9*29$

$UV = \sqrt{9} *\sqrt{29$

$UV = 3\sqrt{29$

So:

$cos V= \frac{TV}{UV}$

$cos\ V = \frac{6}{3\sqrt{29}}$

$cos\ V = \frac{2}{\sqrt{29}}$

Rationalize:

$cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}$

$cos\ V = \frac{2\sqrt{29}}{29}$

8 0

3 years ago

Which of the following expressions is equivalent to the expression a^2/3

vladimir1956 [14]

∛a² → C

From the ' law of exponents '

$a^{\frac{m}{n} }$ = $\sqrt[n]{a^{m} }$

3 0

3 years ago

What is the length of the base if the area is 32 cmand the height is 4 cm

vovikov84 [41]

Answer:

128,8,28,36

Step-by-step explanation:

if u multiply 32 times 4 u get 128 but if u subtract them u get 28

but if u divide them then u get 8 but if u also add them u get 36

7 0

3 years ago