All categories

3 years ago

Least to greatest 913.601 912.21 913.61 912.202

Mathematics

1 answer:

icang [17]3 years ago

3 0

Answer:

Least to greatest

Step-by-step explanation:

912.202

912.21

913.601

913.61

Add zero's next time, (to 912.21 and 913.61 . It could help.)

You might be interested in

If 4/7 = x/161 <br><br> Then x = ?

stepan [7]

Setting up the proportion ,you get that x=92.

3 0

3 years ago

PLZZZZ HURRY ILL GIVE BRAINLEST POINTS PLZZZZ I NEED A 100% ON THIS TEST

yuradex [85]

Answer:

y=2/3-1

Step-by-step explanation:

Two coordinate points are (-3,-3) and (3,1). If you use Y2-Y1/X2-X1, you will find the slope. Then use y=mx+b to find the equation.

More detailed:

1+3/3+3 ** It is + because when there are minus signs it turns to a plus

4/6 Then simplify it

2/3

Now that the slope is found, we need to use y=mx+b

(I used the point (3,1)) 1=2/3(3)+b

1=2+b

-1=b

I hope this is helpful gl on the test! :)

7 0

2 years ago

If (−4, 11) and (−6, 5) are the endpoints of a diameter of a circle, what is the equation of the circle?

lora16 [44]

Answer:

A. $(x+5)^2+(y-8)^2=100$

Step-by-step explanation:

1. The standard form of the equation of a circle is $(x-h)^{2} + (y-k)^2=r^2$

2. To find the center we require the midpoint of the 2 given points

center = $[\frac{1}{2}(-4-6),\frac{1}{2}(11+5)]$

=(-5,8)

3. The radius is the distance from the centre to either of the 2 given points calculate the radius using the distance formula

d= $\sqrt{(x_{2}+x_{1})^{2} +(y_{2}-y_{1})^{2}$

let $(x_{1},y_{1})= (-5,8) \\$ and $(x_2,y_2)=(-4,11)$

r= $\sqrt{(-4+5)^2+(11-8)^2} =\sqrt{81+9}=10$

--> $(x-(-5)^2+(y-8)^2=10^2$

--> $(x+5)^2+(y-8)^2=100$

4 0

3 years ago

Read 2 more answers

Draw and label ray RT

Keith_Richards [23]

You need a picture to lable and draw it so we can awnser your question

6 0

3 years ago

To obtain the area of a sector, what fraction is multiplied by the area of a circle (A = πr2)?

romanna [79]

Let r be a radius of a given circle and α be an angle, that corresponds to a sector.

The circle area is $A=\pi r^2$ and denote the sector area as $A_1$ .
Then $\dfrac{A_1}{A}= \dfrac{\alpha}{2\pi}$ (the ratio between area is the same as the ratio between coresponding angles).

$A_1=\dfrac{\alpha}{2\pi} \cdot A=\dfrac{\alpha}{2\pi} \cdot \pi r^2= \dfrac{r^2\alpha}{2}$ .

6 0

3 years ago