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allochka39001 [22]
3 years ago
9

Least to greatest 913.601 912.21 913.61 912.202

Mathematics
1 answer:
icang [17]3 years ago
3 0

Answer:

Least to greatest

Step-by-step explanation:

912.202

912.21

913.601

913.61

Add zero's next time, (to 912.21  and 913.61 . It could help.)

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If 4/7 = x/161 <br><br> Then x = ?
stepan [7]

Setting up the proportion ,you get that x=92.


3 0
3 years ago
PLZZZZ HURRY ILL GIVE BRAINLEST POINTS PLZZZZ I NEED A 100% ON THIS TEST
yuradex [85]

Answer:

y=2/3-1

Step-by-step explanation:

Two coordinate points are (-3,-3) and (3,1). If you use Y2-Y1/X2-X1, you will find the slope. Then use y=mx+b to find the equation.

More detailed:

1+3/3+3 ** It is + because when there are minus signs it turns to a plus

4/6 Then simplify it

2/3

Now that the slope is found, we need to use y=mx+b

(I used the point (3,1))  1=2/3(3)+b

                                    1=2+b

                                    -1=b

I hope this is helpful gl on the test! :)

7 0
2 years ago
If (−4, 11) and (−6, 5) are the endpoints of a diameter of a circle, what is the equation of the circle?
lora16 [44]

Answer:

A. (x+5)^2+(y-8)^2=100

Step-by-step explanation:

1. The standard form of the equation of a circle is (x-h)^{2} + (y-k)^2=r^2

2. To find the center we require the  midpoint   of the  2 given points

center =[\frac{1}{2}(-4-6),\frac{1}{2}(11+5)]

=(-5,8)

3. The radius is the distance from the centre to either of  the 2 given points calculate the radius using the  distance formula

d= \sqrt{(x_{2}+x_{1})^{2} +(y_{2}-y_{1})^{2}

let (x_{1},y_{1})= (-5,8) \\ and (x_2,y_2)=(-4,11)

r=\sqrt{(-4+5)^2+(11-8)^2} =\sqrt{81+9}=10

--> (x-(-5)^2+(y-8)^2=10^2

--> (x+5)^2+(y-8)^2=100

4 0
3 years ago
Read 2 more answers
Draw and label ray RT
Keith_Richards [23]
You need a picture to lable and draw it so we can awnser your question
6 0
3 years ago
To obtain the area of a sector, what fraction is multiplied by the area of a circle (A = πr2)?
romanna [79]
Let r be a radius of a given circle and α be an angle, that corresponds to a sector.

The circle area is A=\pi r^2 and denote the sector area as A_1. 
Then  \dfrac{A_1}{A}= \dfrac{\alpha}{2\pi}  (the ratio between area is the same as the ratio between coresponding angles).

A_1=\dfrac{\alpha}{2\pi} \cdot A=\dfrac{\alpha}{2\pi} \cdot \pi r^2= \dfrac{r^2\alpha}{2}.

6 0
3 years ago
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