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Tcecarenko [31]
3 years ago
15

What is 1/5 miles in units to 1/65 hours

Mathematics
2 answers:
Anastaziya [24]3 years ago
7 0

Answer:

13m/h

Step-by-step explanation:

1/5m=1/65h

65/5m=h

13m=h

13 miles per hour.

Marina86 [1]3 years ago
4 0

Answer:

13/65 miles in 1/65 of an hour, I believe is the answer you're looking for. Hope this helped!

Step-by-step explanation:

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Help help help help pls​
almond37 [142]

Answer:

Range of the function → {24, 375}

Step-by-step explanation:

Domain of the function f(x) = 3x³ is {2, 5}

we have to find the range when its domain is {2, 5}

Since x-values of any function define the domain and y-values define the range.

For x = 2,

f(2) = 3(2)³ = 24

For x = 5,

f(5) = 3(5)³ = 375

Therefore, range of the given function for the given domain will be {24, 375}.

4 0
3 years ago
Using descriptive statistics, you have found out that it takes an average of 40 minutes to complete a mid-term examination in IS
choli [55]

Answer:

b. exam completion time is negatively skewed

Step-by-step explanation:

A data distribution is said to be negatively skewed when <em>median</em> value of the distribution is higher than the <em>average</em> value of the distribution.

In this example

  • average mid-term completion time is 40 minutes  
  • median mid-term completion time is 55 minutes.

thus median > mean, so the mid-term completion time is negatively skewed. Negatively skewed distributions are also called left-skewed.

6 0
3 years ago
A silo is not the shape of a cone. The silo is 8 meters tall and it's base has a diameter of 3 meters. Soybeans cost $414 per cu
Gnom [1K]

Answer:

$7803.72

Step-by-step explanation:

We have been given that a silo is in the shape of a cone. The silo is 8 meters tall and it's base has a diameter of 3 meters. Soybeans cost $414 per cubic meter. We are asked to find the total cost to fill the silo with soybeans.

First of all, we will find the volume of silo using volume of cone formula.

\text{Volume of cone}=\frac{1}{3}\pi r^2 h, where,

r = radius

h = Height

We know that radius is half the diameter, so radius of silo would be r=\frac{3}{2}=1.5.

\text{Volume of cone}=\frac{1}{3}\pi (1.5\text{ m})^2 (8)\text{ m}

\text{Volume of cone}=\frac{1}{3}\pi\times 2.25\text{ m}^2 (8)\text{ m}

\text{Volume of cone}=\pi\times 0.75\text{ m}^2 (8)\text{ m}

\text{Volume of cone}=\pi\times 6\text{ m}^3

\text{Volume of cone}=18.8495559\text{ m}^3

Now we will multiply total volume by $414 to find total cost.\

\text{Total cost of soybeans}=\$414 \times 18.8495559

\text{Total cost of soybeans}=\$7803.7161426

\text{Total cost of soybeans}\approx \$7803.72

Therefore, it will cost $7803.72 to fill the silo with soybeans.

5 0
3 years ago
23.0833333333 in fraction form
Black_prince [1.1K]

Answer:

230833333333/10000000000

Step-by-step explanation:

Well to write this as a fraction you will first write 23.0833333333 as our numerator

Now you would multiply numerator by denominator which you could put 1 as denominator and multiply by 10 and you get your whole number/your answer.

Hope this helps have a great day:)

4 0
2 years ago
Write an equation of a line that is perpendicular to the line y=2/3x and passes through origin
sesenic [268]

keeping in mind that perpendicular lines have negative reciprocal slopes, hmmm what's the slope of the equation above anyway?

\bf y = \cfrac{2}{3}x\implies y = \stackrel{\stackrel{m}{\downarrow }}{\cfrac{2}{3}}x+0\qquad \impliedby \begin{array}{|c|ll} \cline{1-1} slope-intercept~form\\ \cline{1-1} \\ y=\underset{y-intercept}{\stackrel{slope\qquad }{\stackrel{\downarrow }{m}x+\underset{\uparrow }{b}}} \\\\ \cline{1-1} \end{array} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{perpendicular lines have \underline{negative reciprocal} slopes}} {\stackrel{slope}{\cfrac{2}{3}}\qquad \qquad \qquad \stackrel{reciprocal}{\cfrac{3}{2}}\qquad \stackrel{negative~reciprocal}{-\cfrac{3}{2}}}

so we're really looking for the equation of a line whose slope is -3/2 and runs through (0,0).

\bf (\stackrel{x_1}{0}~,~\stackrel{y_1}{0})~\hspace{10em} \stackrel{slope}{m}\implies -\cfrac{3}{2} \\\\\\ \begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{-\cfrac{3}{2}}(x-\stackrel{x_1}{0})\implies y=-\cfrac{3}{2}x

7 0
3 years ago
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