I don’t think I wanna do this

Mathematics

2 answers:

Vedmedyk [2.9K]3 years ago

7 0

$89.10 is the best guess.

damaskus [11]3 years ago

7 0

Answer:

nither do i

Step-by-step explanation:

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(x+6)(x-4)=

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3 years ago

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LekaFEV [45]

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3 years ago

At Noise Pollution Cellular, plan A is $30.00 per month and $5.00 for every gigabyte of data. Plan B is $50.00 per month and $2.

Verdich [7]

We need to find an equation for each situation. Let x be the number of GB of data used.

Statement 1: At Noise Pollution Cellular, plan A is $30.00 per month and $5.00 for every gigabyte of data used.

Plan A cost equation $C(x) = 30 + 5x$

Statement 2: At Noise Pollution Cellular, Plan B is $50.00 per month and $2.00 for every gigabyte of data used.

Plan B cost equation $C(x) = 50 + 2x$

Number of GB of data for which both the plan A and plan B cost are same.

$30+5x=50+2x \\ Subtracting \; 2x \; \& \;30\; on\; both\; sides\; \\ \\30+5x-2x-30=50-30+2x-2x \\Combining \; like \; terms\\\\3x=20\\Dividing \; like \; terms\\\\ \frac{3x}{3}=\frac{20}{3} \\ \\x=6\frac{2}{3}$

When

$x=6 \\\\ Plan \; A \; Cost = 30+5(6)=30+30=\$60\\ Plan \; B \; Cost = 50+2(6)=50+12= \$72\\ \\ From \; 5\leq x\leq 6\frac{2}{3} , \; Plan \; A \; is \; Cheaper!$

When

$x = 7\\\\ Plan \; A \; Cost= 30 + 5(7) =30+35 = \$65\\\\Plan \; B \; Cost = 50 + 2(7)=50+14=\$64 \\ \\ From \; 6\frac{2}{3} \leq x \leq 8, \; Plan\; B \; is \; Cheaper !$